Answer:
The answer to the problem is -15.52
Answer:
The two integers the square root of 62 falls between are 7, and 8.
Step-by-step explanation:
the square root of 62 is 7.874.... so the numbers that it is between are 7 and 8 because its more than 7 but less than 8
=Y2-10Y
We move all terms to the left:
-(Y2-10Y)=0
We add all the numbers together, and all the variables
-(+Y^2-10Y)=0
We get rid of parentheses
-Y^2+10Y=0
We add all the numbers together, and all the variables
-1Y^2+10Y=0
a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
Y1=−b−Δ√2aY2=−b+Δ√2a
Δ‾‾√=100‾‾‾‾√=10
Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10
Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0
3,000,000+20,000+8,000+2=3,028,002
Also next time, right the numbers with comas please.