If a triangle has side lengths 5 cm, 18 cm, and 12 cm, is it a right triangle?
1 answer:
Answer:
No, it's not a right triangle.
Step-by-step explanation:
1. The Pythagorean Theorem states that the area of the square whose side is the hypotenuse (longest side of a right triangle) is equal to the sum of the area of the squares from the two other sides.
2. The longest side in this "triangle" has 18 centimeters, and the other 2 sides are 5 and 12 centimeters.
3. Let's apply the Pythagorean Theorem to see if 5^2 + 12^2 = 18^2
4. Okay, so the sum of the area of the squares from the two other sides is not equal to the hypotenuse squared, therefore, it's not a right triangle.
(Plus, it's not even a triangle because 7 < x < 17, and the third "side", 18, is not between 7 and 17.)
You might be interested in
Answer:
option D is true.
Step-by-step explanation:
The right-angled triangle is shown.
From the right-angled triangle,
The angle Ф = 60°
We know that the trigonometric ratio
tan Ф = opposite / adjacent
- opposite = 4
- adjacent = n
Thus,
tan 60 = 4 / n
√3 = 4/n
n = 4/√3
Thus,
n = 4/√3
= (4 × √3) / (√3 × √3)
= 4√3 / 3
Thus,
n = 4√3 / 3
Using Pythagorean theorem
m = √n²+4²
Thus,
- n = 4√3 / 3
Therefore, option D is true.
7x+2
Step-by-step explanation:
add all the sides of the pentagon and make it equal to the perimeter of the square which is 4y
sides of the pentagon are
5x+3
2x+3
7x+4
9x-10
5x+8
28x+8=4y
7x+2 = y
7x+2 = answer
gathmath
gathmathier6961
another way :
in a standardized test you may want to use real numbers
make x equal a prime number like 3
so then the sides are
18
9
25
17
23
=
92
then divide by 4
23
then divide by 3
which is 7 remainder of 2
which is
7x+2
