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aleksandr82 [10.1K]
3 years ago
6

Mrs.Connners went to a shopping mall with $250 in her wallet. At the store, she bought a coat and spent 3/5 of the money she had

in her wallet. How much money, in dollars, did she pay for the coat?
Mathematics
2 answers:
denpristay [2]3 years ago
7 0

Answer:

$150

Step-by-step explanation:

$250 ÷ 5 = 50

50 · 3 = 150

LenKa [72]3 years ago
3 0

Step-by-step explanation:

step 1. 250(3/5) = 50(3) = 150.

step 2. She spent $150 for the coat.

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Find the interquartile range (IQR) of the data in the box plot below. A horizontal boxplot titled Magnitude of earthquakes, is p
tresset_1 [31]

Answer:

IQR = 3

Step-by-step explanation:

Interquartile range, which is abbreviated as IQR, is just the difference between the upper quartile (where the box ends) and the lower quartile (where the box starts). AS it is given in the question that that box starts from 4 and ends at . The interquartile range IQR is simply:

IQR = 7 - 4 = 3

The values of data are usually clustured around some central value. Interquartile range tells us how spread out these middle values. It also tells when some values are too far from the central value. The values which are too far are also termed as outlier values

8 0
3 years ago
Read 2 more answers
What is the equation in slope-intercept form for the line that passes through the points
Tju [1.3M]

Answer:

check the file to see the answer i added a screen shot of the answer

Step-by-step explanation:

8 0
3 years ago
PLEAS HELP ME
GarryVolchara [31]

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{Table~A}{\begin{array}{ccll} x&y\\ \cline{1-2} 60&48\\70&56\\80&64 \end{array}}~\hspace{7em} \stackrel{Table~B}{\begin{array}{ccll} x&y\\ \cline{1-2} 20&24\\30&36\\40&48 \end{array}} \\\\[-0.35em] ~\dotfill


\bf \textit{for table A, we know that } \begin{cases} x=60\\ y=48 \end{cases}\implies 48=k60\implies \cfrac{48}{60}=k \\\\\\ \cfrac{4}{5}=k\qquad therefore\qquad \boxed{y=\cfrac{4}{5}x} \\\\\\ \textit{for table B, we know that } \begin{cases} x=30\\ y=36 \end{cases}\implies 36=k30\implies \cfrac{36}{30}=k \\\\\\ \cfrac{6}{5}=k\qquad therefore\qquad \boxed{y=\cfrac{6}{5}x}

4 0
3 years ago
Hey can you please help me posted picture of question
MAXImum [283]
Answer:
The solutions of the equation are:
4/3 and 5/8

Explanation:
To get the solution of the equation, we can either solve it algebraically or graphically.

1- algebraic solution:
The general form of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
24x² - 47x + 20 = 0
By comparison, we can find that:
a = 24
b = -47
c = 20

Now, to get the roots, we will use the quadratic equation shown in the attached image.

Substituting in the equation, we would find that:
either x = \frac{-(-47) +  \sqrt{(-47)^2-4(24)(20)} }{2(24)} =  \frac{4}{3}
or x = \frac{-(-47) - \sqrt{(-47)^2-4(24)(20)} }{2(24)} = \frac{5}{8}

2- graphical solution:
To get the solution means to get the values of the x-intercepts.
Graphing the function (see attached image), we would find that the solutions are:
0.625 which is equivalent to 5/8 
and 1.3333 which is equivalent to 4/3

Hope this helps :)

3 0
3 years ago
0.05%<br> Convert to a decimal
liraira [26]

Answer:

0.0005.

Step-by-step explanation:

Divide by 100.

Move the decimal point  2 places to the left.

3 0
3 years ago
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