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2 years ago

Explain how you know that each pair of triangles are similar.

Mathematics

1 answer:

xenn [34]2 years ago

8 0

If two pairs of corresponding angles in a pair of triangles are congruent, then the triangles are similar. We know this because if two angle pairs are the same, then the third pair must also be equal. When the three angle pairs are all equal, the three pairs of sides must also be in proportion.

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To prepare for a bake-off, Chad used 520 grams of flour each day for 2 weeks. How many kilograms did Chad use in those 2 weeks?

Shalnov [3]

Answer:

7.280 k

Step-by-step explanation:

Given that 1 g = 0.001 k

If he uses 520 grams of flour each day for 2 weeks, since there are 7 days in a week, the total weight of flour used in two weeks

= 520 g * 2 * 7

= 7280 g

In kilograms

Since

1 g = 0.001 k

7280 g = 7280/1 * 0.001 k

= 7.280 k

3 0

2 years ago

Brittany is arranging her shoes. For the amount of shoes she has, she knows she can use either rows of 4 with none left over, or

yawa3891 [41]

Answer:

12 shoes

Step-by-step explanation:

Because 6 times 2 is 12 and 4 times 3 is 12. And that is the lowest common number that they share.

7 0

2 years ago

Read 2 more answers

URGENT HELP *read photo for both questions*

solniwko [45]

SeconAnswer:

Step-by-step explanation:

First question answer is 390.66 m

1 mile_1609.34 m

1000m=1km

2km=2x1000=2000m

2000km - 1609.34m=390.66m

Se ond question 6x10000=60000cm2

3 0

2 years ago

How this concepts are used in different situations?

andriy [413]

Answer:

Positive thinking is all of mind also positive

Step-by-step explanation:

4 0

2 years ago

77. the volume of a cube is increasing at a rate of <img src="https://tex.z-dn.net/?f=10%20%5Cmathrm%7B~cm%7D%5E%7B3%7D%20%2F%20

Colt1911 [192]

Answer:

$\displaystyle \frac{4}{3}\text{cm}^2/\text{min}$

Step-by-step explanation:

Given

$\displaystyle \frac{dV}{dt}=10\:\text{cm}^3/\text{min}\\ \\V=s^3\\\\SA=6s^2\\\\\frac{d(SA)}{dt}=?}\:;s=30\text{cm}$

Solution

(1) Find the rate of the cube's edge length with respect to time at s=30:

$\displaystyle V=s^3\\\\\frac{dV}{dt}=3s^2\frac{ds}{dt}\\ \\10=3(30)^2\frac{ds}{dt}\\ \\10=3(900)\frac{ds}{dt}\\\\10=2700\frac{ds}{dt}\\\\\frac{10}{2700}=\frac{ds}{dt}\\\\\frac{ds}{dt}=\frac{1}{270}\text{cm}/\text{min}$

(2) Find the rate of the cube's surface area with respect to time at s=30:

$\displaystyle SA=6s^2\\\\\frac{d(SA)}{dt}=12s\frac{ds}{dt}\\ \\\frac{d(SA)}{dt}=12(30)\biggr(\frac{1}{270}\biggr)\\\\\frac{d(SA)}{dt}=\frac{360}{270}\biggr\\\\\frac{d(SA)}{dt}=\frac{4}{3}\text{cm}^2/\text{min}$

Therefore, the surface area increases when the length of an edge is 30 cm at a rate of $\displaystyle \frac{4}{3}\text{cm}^2/\text{min}$ .

6 0

1 year ago