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Pie
2 years ago
13

Name three different properties you can test before and after a chemical reaction​

Chemistry
1 answer:
Anvisha [2.4K]2 years ago
3 0

Answer:

reactivity, flammability, and if they rust

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Find the mole fraction of Methanol CH3OH and water in a solution prepared by dissolving 4.5 g of alcohol in 40 g of H2O.
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How many number of orbitals are in Potassium (K)?<br><br> 1s^2 2s^2 2p^6 3s^2 3p^6 4s^1
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Explanation:

Each orbital can only carry at most 2 electrons wih opposite spins.

The first 3 shells are fully filled, giving 9 orbitals.

There is an extra electron in 4s, which gives another orbital. (even though it is not filled yet)

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6 0
3 years ago
A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from
sweet-ann [11.9K]

Answer:

T_i~=163.1 ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

<u>Initial temperature of gold= Unknow</u>

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the <u>heat equation</u>:

Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT

Q_A_u=m_A_u*Cp_A_u*deltaT

We can relate these equations if we take into account that <u>all heat of gold is transfer to the water</u>, so:

m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT

Now we can <u>put the values into the equation</u>:

60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)

Now we can <u>solve for the initial temperature of gold</u>, so:

T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20

T_i~=163.1 ºC

I hope it helps!

5 0
2 years ago
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