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Pie
2 years ago
13

Name three different properties you can test before and after a chemical reaction​

Chemistry
1 answer:
Anvisha [2.4K]2 years ago
3 0

Answer:

reactivity, flammability, and if they rust

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Which of the following statements is correct?
WITCHER [35]

Answer: A

Explanation: i took the test

5 0
2 years ago
A driver blows 0.75 -L air bubble 10 m under water. As it rises to the surface, the pressure goes from 2.25 atm to 1.03 atm. Wha
kakasveta [241]

Answer:

1.64 L

Explanation:

P₁V₁ = P₂V₂

P₁ = 2.25 atm

V₁ = 0.75 L

P₂ = 1.03 atm

V₂ = ?

(2.25 atm)(0.75 L) = (1.03 atm)V₂

[(2.25 atm)(0.75 L)]/(1.03 atm) = V₂

V₂ = 1.64 L

3 0
3 years ago
In designing the experiment, the researchers used which type of 32p labeled atp?.
lilavasa [31]

In designing the experiment, the researchers used Y32P-ATP.

<h3>What is ATP?</h3>

Adenosine triphosphate (ATP) is an organic substance and a hydro-trope that provides energy for a variety of functions in

  • living cells
  • including muscular contraction
  • nerve impulse propagation
  • condensate dissolving
  • and chemical synthesis

Researchers used Y32P-ATP Because the Y-phosphate of ATP is used for phosphoryl transfer by kinases. As a result, Y32P-ATP is required for the experiment.

Hence the used ATP is Y32P-ATP.

To know more about ATP, visit the below link:

brainly.com/question/893601

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3 0
2 years ago
The equilibrium constant, Kc, for the following reaction is 4.76×10-4 at 431 K. PCl5(g) PCl3(g) + Cl2(g) When a sufficiently lar
soldier1979 [14.2K]

Answer:

Explanation:

Step 1: Data given

The equilibrium constant, Kc, for the following reaction is 4.76 * 10^-4 at 431 K

The equilibrium concentration of Cl2(g) is  0.233 M

Step 2: The balanced equation

PCl5(g)  ⇄ PCl3(g) + Cl2(g)

Step 3: The initial concentration

[PCl5]= Y M

[PCl] = 0M

[Cl2] = 0M

Step 4: Calculate the concentration at equilibrium

[PCl5] = Y + X M = Y - 0.233 M

[PCl]= XM = 0.233 M

[Cl2]= XM = 0.233 M

Step 5: Define Kc

Kc =  [Cl2]* [PCl3] / [PCl5]

4.76 * 10^-4 = 0.233² / (Y -0.233)

0.000476 = 0.05429 / (Y - 0.233)

Y - 0.233 = 0.05429 / 0.000476

Y - 0.233 = 114.05 M

Y = 114.283 M = the initial concentration

The concentration of PCl5 at the equilibrium is 114.05 M

8 0
3 years ago
In a laboratory demonstration, a balloon filled with methane and oxygen was exposed to a flame. The result was a brief, large fl
Savatey [412]

Answer:

<u>The equation is not correct: </u>

[CH4 + O2 → CO2 + 2H2O]

Explanation:

The chemical formulas for methane, oxygen, and carbon dioxide are correct, but the equation is not balanced, so we really don't know idf the overall reaction is written correctly.

Let's balance the reaction:

CH4 + O2 → CO2

We need to have the same numbers of atoms on both sides.  

Count the numbers of each atom:

<u>Element</u>    <u>Reactants</u>    <u>Products</u>    <u>Difference</u>

 C                         1              1                  0                  Balanced

 H                         4              0                -4                  XXX!!!!

 O                         2              2                 0                  Balanced

The hydrogens aren't showing up in the products.  In fact, there is a product missing entirely from the reaction, H2O, water.  The basic reaction is:

CH4 + O2 → CO2 + H2O

Now balance this reaction:

<u>Element</u>    <u>Reactants</u>    <u>Products</u>    <u>Difference</u>

 C                         1              1                  0                  Balanced

 H                         4              2                -2                  Hmmmm . . .

 O                         2              3                 1                  Uh = oh . . .

This reaction is not possible - there are either too many or too few element atoms (the "Difference").

We can adjust the coefficients for each of the molecules to balanced the equation.  This is a bit tricky, but it consists of trying some coefficients that would make things balance.  Only whole number coefficients are allowed in the final answer, although fractions might be used in the process to help find the whole numbers.

We need 2 H2O molecules to account for the 4 hydrogens on a single methane molecule

Step 1:  CH4 + O2 → CO2 + 2H2O

That leads to:

<u>Element</u>    <u>Reactants</u>    <u>Products</u>    <u>Difference</u>

 C                         1               1                 0                  Balanced

 H                         4              4                0                   Balanced

 O                         2              4                 2                  Darn

We need more oxygen atoms, so:

Step 2:  CH4 + 2O2 → CO2 + 2H2O

This leads to:

<u>Element</u>    <u>Reactants</u>    <u>Products</u>    <u>Difference</u>

 C                         1               1                  0                  Balanced

 H                         4              4                 0                   Balanced

 O                         4              4                 0                   Balanced

This is a balanced reaction, and the correct chemical equation.

3 0
2 years ago
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