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JulijaS [17]
3 years ago
6

What are two ways to describe concentration? How do they differ from one another?

Chemistry
2 answers:
Alchen [17]3 years ago
8 0
It can be expressed in several ways: molarity (moles of solute per liter of solution); mole fraction, the ratio of the number of moles of solute to the total number of moles of substances present; mass percentage, the ratio of the mass of the solute to the mass of the solution times 100; parts per thousand (ppt), grams ...
adell [148]3 years ago
3 0

Answer:

no .........................

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Use the formula for pressure to determine the weight of a box that creates a pressure of 1,065 N/cm 2 when resting on a 17.0-cm
S_A_V [24]
Force /Area = Pressure
Force = Pressure * Area
<span>Force = 1065 * 17 = 18105 N</span>
7 0
3 years ago
Read 2 more answers
Within an atom, electrons A. are in motion inside the nucleus. B. are in motion outside the nucleus. C. are inside the nucleus a
marin [14]

Hello! The correct answer is, B. are in motion outside the nucleus.


I hope this helped!

4 0
4 years ago
Read 2 more answers
YOU DO:
mihalych1998 [28]

Answer:

67.1%

Explanation:

Based on the chemical equation, if we determine the moles of sodium carbonate, we can find the moles of NaHCO₃ that reacted and its mass, thus:

<em>Moles Na₂CO₃ - 105.99g/mol-:</em>

6.35g * (1mol / 105.99g) = 0.0599 moles of Na₂CO₃ are produced.

As 1 mole of sodium carbonate is produced when 2 moles of NaHCO₃ reacted, moles of NaHCO₃ that reacted are:

0.0599 moles of Na₂CO₃ * (2 moles NaHCO₃ / 1 mole Na₂CO₃) = 0.1198 moles of NaHCO₃

And the mass of NaHCO₃ in the sample (Molar mass: 84g/mol):

0.1198 moles of NaHCO₃ * (84g / mol) = 10.06g of NaHCO₃ were in the original sample.

And percent of NaHCO₃ in the sample is:

10.06g NaHCO₃ / 15g Sample * 100 =

<h3>67.1%</h3>
7 0
3 years ago
Is bleach liquid starch? <br> Yes or No
Jobisdone [24]

Answer:

O it's not

Explanation:

Have a great day!

8 0
2 years ago
When a saturated solution of NH4Br dissolved in 100 grams of water is cooled from 60°C to 30°C, how much NH4Br will precipitate?
stepladder [879]

Answer:

m_{precipitated}=24.8g

Explanation:

Hello,

In this case, since at 60 °C, 108 grams of ammonium bromide are completely dissolved in 100 grams of water for a saturated solution, once it is cooled to 30 °C, wherein only 83.2 grams are completely dissolved in 100 grams of water, the following mass will precipitate:

m_{precipitated}=108g-83.2g\\\\m_{precipitated}=24.8g

Best regards.

8 0
3 years ago
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