Non metals acid subcategories
1. carbon dioxide is a gas at low temperatures at mars because in the oxidizing environment organic compounds are oxidized to form carbon dioxide.
2. The 1 electron in outermost shell of Na is shared with 7 electrons of outermost shell of chlorine giving neutral charge on compound.
3. Electrostatic force of attraction is between the metal and non-metal.
4. When metal and non metal exchange electrons to form a neutral or no charge compound it is said to have form ionic bonds.
Explanation:
1. Temperature at Mars is very low -80 Fahrenheit (-60 degrees) because water is not present in the planet. Carbon dioxide is abundant in Mars. The atmosphere is oxidizing at Mars which oxidizes the organic compounds and forms carbon dioxide.
2. NaCl combines by sharing of electrons forming ionic bonding. Different atoms of the different element share electrons to form ionic bonds. Such bond is formed when electrons is transferred between the atoms. In the NaCl, Na has 1 electron (electropositive) in its outer shell and chlorine has 7 electrons (electronegative). Both share the electrons getting their octet complete and a neutral charge on the compound formed.
3. Electrostatic force of attraction is between the metal and non-metal when bond is formed. The ionic bonds is formed between metal and non metals when electron exchange takes place. The electrostatic force is the attraction between two opposite charges on the ion.
4. When a metal and non metal exchange electrons in which metal is electropositive and non metal is electronegative the bonds form is called ionic bond. The electron is transferred from metal to non metal and thus giving neutral charge on the compound i.e. the outer shell has its octet complete.
Answer:
Higher K at very high temperatures.
Explanation:
It is inferred is K is significantly greater at very high temperatures, allowing high production at low cost.
Density = mass/volume
for finding mass, density of liquid is required
<h3>
Answer:</h3>
1.24 × 10³ kJ/mol
<h3>
Explanation:</h3>
From the question we are given;
Heat capacity of the calorimeter =23.3 kJ/°C
Temperature change, ΔT = 76°C - 35°C
= 41 °C
Mass of ethanol = 35.6 g
Molar mass of ethanol = 46.07 g/mol
We are required to determine the molar enthalpy
We can use the following steps:
<h3> Step 1 : Calculate the heat change of the reaction</h3>
Heat change will be equivalent to heat gained by the calorimeter.
Therefore;
Heat = heat capacity × change in temperature
Q = CΔT
= 23.33 kJ/°C × 41°C
= 955.3 kJ
<h3>Step 2 : Calculate the moles of ethanol burned </h3>
Moles = mass ÷ Molar mass
Therefore;
Moles of ethanol = 35.6 g ÷ 46.07 g/mol
= 0.773 moles
<h3>Step 3: Calculate the molar enthalpy of the reaction </h3>
Heat change for 0.773 moles of ethanol is 955.3 kJ
0.773 moles = 955.3 kJ
1 mole will have ,
= 955.3 kJ ÷ 0.773 moles
= 1235.83 kJ/mol
= 1.24 × 10³ kJ/mol
But since the reaction is exothermic (release of heat) then the enthalpy change will have a negative sign.
Thus;
ΔH = -1.24 × 10³ kJ/mol
