Answer:
See explanation below
Explanation:
The question is incomplete. However, here's the missing part of the question:
<em>"For the following reaction, Kp = 0.455 at 945 °C: </em>
<em>C(s) + 2H2(g) <--> CH4(g). </em>
<em>At equilibrium the partial pressure of H2 is 1.78 atm. What is the equilibrium partial pressure of CH4(g)?"</em>
With these question, and knowing the value of equilibrium of this reaction we can calculate the partial pressure of CH4.
The expression of Kp for this reaction is:
Kp = PpCH4 / (PpH2)²
We know the value of Kp and pressure of hydrogen, so, let's solve for CH4:
PpCH4 = Kp * PpH2²
*: You should note that we don't use Carbon here, because it's solid, and solids and liquids do not contribute in the expression of equilibrium, mainly because their concentration is constant and near to 1.
Now solving for PpCH4:
PpCH4 = 0.455 * (1.78)²
<u><em>PpCH4 = 1.44 atm</em></u>
The question is incomplete as it does not have the options which are:
A) anaphase
B) prophase
C) telophase
D) metaphase
E) interphase
Answer:
The correct answer will be option-D
Explanation:
Colchicine is a drug obtained from the <em>Colchicum autumnale</em> which is a poisonous European flowering plant. The drug is used to treat joint swelling and gout.
Colchicine shows its effect during the cell division cycle especially during the division of nuclear content. When the cell is in metaphase and is preparing for the anaphase, the colchicine inhibits the polymerisation of the microtubules. The inhibition of microtubules inhibits the assembly of the mitotic spindle as a result of this the DNA do not move into new daughter cells.
Thus, option-D is the correct answer.
The experimental mole ratio of silver chloride to barium chloride is calculated as below
fin the mole of each compound
mole= mass/molar mass
moles of AgCl = 14.5g/142.5 g/mol = 0.102 moles of AgCl
moles of BaCl2 = 10.2 g/208 g/mol = 0.049 moles of BaCl2
find the mole ratio by dividing each mole with the smallest mole(0.049)
AgCl= 0.102/0.049 =2
BaCl2 = 0.049/0.049 =1
therefore the mole ratio AgCl to BaCl2 is 2 :1
