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kolezko [41]
3 years ago
14

5.06,5.14,5.1,5.01 smallest to largest​

Mathematics
1 answer:
beks73 [17]3 years ago
3 0
5.01, 5.06, 5.14, 5.1
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144 coins are divided equally among some
nalin [4]

Answer:

Consider the number of children to be x.

So, 144 coins were divided amongst x children.

For x-3 children, each child would have 16 coins

So, (x-3)*16=144

Solving for x, x-3=144/16

or x-3=9

or x=9+3=12

Answer is 12

3 0
3 years ago
Read 2 more answers
Solve for x.<br> 4<br> 15<br> 6<br> X<br> x = [?]<br> Enter the number in decimal form
posledela

Answer:

66

Step-by-step explanation:

x / 6 + 4 = 15

To find x ;

Subtrac4 from both sides

x / 6 + 4 - 4 = 15 - 4

x / 6 = 11

Multiply both sides by 6

x / 6 * 6 = 11 * 6

x = 66

Value of x = 66

6 0
3 years ago
To make a specific orange color, a painter uses 14 of a can of red paint and 12 of a can of yellow paint. Fill in each statement
Otrada [13]

Answer:  For every 1 can of red paint, the number of yellow paints used by the painter is \frac{6}{7} and

There are approximately 29 cans of yellow paints for 34 cans of red paints.

Step-by-step explanation:

Since we have given that

Number of cans of red paint = 14

Number of cans of yellow paint = 12

According to question, we have to find that for every 1 can of red paint the painter uses what number of yellow paints;

Since the ratio of red paint to yellow paint is given by

14:12\\\\7:6\\\\1:\frac{6}{7}

So, for every 1 can of red paint, the number of yellow paints used by the painter is \frac{6}{7}

Similarly,

If Number of can of red paint is used = 34

So, Number of cans of yellow paint will be

\frac{6}{7}\times 34\\\\=\frac{6\times 34}{7}\\\\=29\ approx.

Hence, there are approximately 29 cans of yellow paints for 34 cans of red paints.

3 0
3 years ago
Help please with this question
choli [55]

Answer:

They lose about 2.79% in purchasing power.

Step-by-step explanation:

Whenever you're dealing with purchasing power and inflation, you need to carefully define what the reference is for any changes you might be talking about. Here, we take <em>purchasing power at the beginning of the year</em> as the reference. Since we don't know when the 6% year occurred relative to the year in which the saving balance was $200,000, we choose to deal primarily with percentages, rather than dollar amounts.

Each day, the account value is multiplied by (1 + 0.03/365), so at the end of the year the value is multiplied by about

... (1 +0.03/365)^365 ≈ 1.03045326

Something that had a cost of 1 at the beginning of the year will have a cost of 1.06 at the end of the year. A savings account value of 1 at the beginning of the year would purchase one whole item. At the end of the year, the value of the savings account will purchase ...

... 1.03045326 / 1.06 ≈ 0.9721 . . . items

That is, the loss of purchasing power is about ...

... 1 - 0.9721 = 2.79%

_____

If the account value is $200,000 at the beginning of the year in question, then the purchasing power <em>normalized to what it was at the beginning of the year</em> is now $194,425.14, about $5,574.85 less.

7 0
3 years ago
Find the angle θθ between the vectors v=2i+kv=2i+k, w=j−3kw=j−3k.
kaheart [24]
Hello : 
v . w = <span>| | v | | × </span><span>| | w | |  cos(</span><span>θ) ....(1)
v(2,0,1)   w(0,1,-3)

</span>v . w = (2)(0)+(0)(1)+(1)(-3) = - 3
| | v | |  = √((2)²+(0)²+(1)²) = <span>√5
</span>| | w |  =  √((0)²+(1)²+(-3)²) = √10
by (1) : 
cos(θ) = (v . w ) /  | | v | | × | | w | |

cos(θ) = = - 3/√50
θ =.....   calculate by 2ind function ( calculator)

4 0
3 years ago
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