Do you want the numbers? If so, it is 763.35 :)
The new equation is (x-2)^2 + (y+4)^2 = 16, the center is (2,-4) and the radius is 4 :)
Answer:
![b= \frac{q - 4a}{4}](https://tex.z-dn.net/?f=b%3D%20%20%5Cfrac%7Bq%20-%204a%7D%7B4%7D%20)
Step-by-step explanation:
ill suppose that you mean : "solve for b" not for d, since there is no d term in the formula given. So:
![q = 4(a + b) \\ q = 4a + 4b \\ 4a + 4b = q \\ 4a + 4b - 4a = q - 4a \\ 4b = q - 4a \\ b = \frac{q - 4a}{4}](https://tex.z-dn.net/?f=q%20%3D%204%28a%20%2B%20b%29%20%5C%5C%20q%20%3D%204a%20%2B%204b%20%5C%5C%204a%20%2B%204b%20%3D%20q%20%5C%5C%204a%20%2B%204b%20-%204a%20%3D%20q%20-%204a%20%5C%5C%204b%20%3D%20q%20-%204a%20%5C%5C%20b%20%3D%20%20%5Cfrac%7Bq%20-%204a%7D%7B4%7D%20)
Answer:
The standard deviation is 6
Step-by-step explanation:
The scores of a given test were normally distributed with a mean of 82.
![\mu = 82](https://tex.z-dn.net/?f=%5Cmu%20%3D%2082)
James received a 67 with a z-score of -2.5
Z score = -2.5
![\bar{x}=67](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D67)
Formula :![Z=\frac{x-\mu}{\sigma}](https://tex.z-dn.net/?f=Z%3D%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D)
![-2.5=\frac{67-82}{\sigma}](https://tex.z-dn.net/?f=-2.5%3D%5Cfrac%7B67-82%7D%7B%5Csigma%7D)
![\sigma = \frac{67-82}{-2.5}](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cfrac%7B67-82%7D%7B-2.5%7D)
![\sigma =6](https://tex.z-dn.net/?f=%5Csigma%20%3D6)
Hence The standard deviation is 6