As the given values are
<span>ΔHf° = –423 kJ/mol
</span>ΔHsub = 119 kJ/mol
IE = 469 kJ/mol
ΔHEA = –301 kJ/mol
BE = 161 kJ/mol
The lattice energy of the compound can be determined by applying formula
U = <span>ΔHf° - </span>ΔHsub - BE - IE - ΔHEA
by putting values
U = -423 - 119 - 161 - 469 - (-301)
solving further
U = -871 kJ/mol
so the lattice energy is 871 kJ/mol
hope it helps
Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
here you go m = (y2-y1)/(x2-x1)
= (11-(-9))/(3-(-1))
= 20/4
= 5
Ann factored the trinomial completely
take out a common factor of 2
2(2x² - 3x - 2 )
to factor the trinomial consider the factors of the product 2 × - 2 = - 4 which sum to - 3
These are - 4 and + 1
Split the middle term using these factors
2x² - 4x + x - 2 ← ( factor by grouping )
= 2x(x - 2) + 1(x - 2) ← ( take out common factor (x - 2) )
=(x - 2)(2x + 1)
4x² - 6x - 4 = 2(x - 2)(2x + 1) ← ( fully factored )
60 : 45 can be simplified to 4 : 3
(divide 60 and 45 by 15 and you’ll get 4:3)
