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2 years ago

HELPPPP ASAP PLSSSSS!!!!!!

Mathematics

1 answer:

densk [106]2 years ago

5 0

Answer:

5.25 + 5.25 = 10.5

8.5 - 3.25 = 5.25

5.25 & 8.5 are the answers consequently

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The cost of a sweatshirt is 175% the cost of a T-shirt. A T-shirt costs $13.

mariarad [96]

Answer:A standard blank t shirt will usually start at around $1 each and go up to $4. These are going to be cotton, good quality shirts. The price difference will vary on manufacturer, brand, color and cut. So a plain white t shirt might only be $1, where the same shirt in navy blue might be $2.

Step-by-step explanation:

If you want a profit of 50% off the retail price, the calculation is straightforward. Let's say the production cost of your t-shirt amount to ₹300. When you multiply it by two, you get ₹600. And that would be the retail price of each t-shirt piece

4 0

2 years ago

Read 2 more answers

jasmine wants to build a 2 5/6 meter long garden path paved with square stones that measure 1/4 meter on each side there will be

patriot [66]

$2 \frac{5}{6}*2= \frac{17}{6}* \frac{2}{1} = \frac{17}{3}= 5\frac{2}{3}$

$5 \frac{2}{3}: \frac{1}{4}= \frac{17}{3}* \frac{4}{1}= \frac{68}{3} =22 \frac{2}{3}$

23 stones will be needed
(you have to round up, since you can't have a fraction of a stone)

4 0

3 years ago

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The amount of rainfall in January in a certain city is normally distributed with a mean of 4.2 inches and a standard deviation o

romanna [79]

Q1 = the exact amount

5 0

3 years ago

On a coordinate plane, how are the locations of the points (1 , -5) and (-1 , 5) related

KengaRu [80]

Answer:

They are a transformation

Step-by-step explanation:

Checked using desmos graphing

8 0

3 years ago

High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers

Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

Step:-1

Given that the mean of the Population = 540HP

Given that the size of the sample 'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

Step(ii):-

Degrees of freedom = n-1 =9-1 =8

t₀.₀₀₅ = 3.3554

The 99% of a confidence interval for the average maximum HP for the experimental engine.

$(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2} + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )$

$(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )$

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

Final answer :-

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

4 0

2 years ago