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3 years ago

And I need help with these too please! I need to find the area of the shaded region please

Mathematics

1 answer:

nignag [31]3 years ago

4 0

Answer:

14m²

Step-by-step explanation:

The shaded triangles are congruent using SAS congruency

The area of shaded is

(½×2×7)×2 m²

(7)×2 m²

14m²

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Need t in degrees not just solve for t

Inessa [10]

An exterior angle is equal to the sum of the two opposite inside angles.

T + 31 = t + t-29

Simplify:

T + 31 = 2t -29

Add 29 to both sides:

T + 60 = 2t

Subtract 1t from both sides:

T = 60

8 0

4 years ago

How much would you need to deposit in an account now in order to have $5000 in the account in 10 years? Assume the account earns

Blababa [14]

Answer:

$12500

Step-by-step explanation:

use si formula

SI=ptr/100

si=5000

t=10

r=4

6 0

3 years ago

My product is 30. The differencd of the two factors is 1. The zum of the two factors is 11. What numbers am i

timurjin [86]

A * b = 30
a - b = 1
a + b = 11

take ur last 2 equations, and add them
a - b = 1
a + b = 11
--------------add
2a = 12
a = 12/2
a = 6

now its just a matter of subbing
a + b = 11
6 + b = 11
b = 11 - 6
b = 5

so a = 6 and b = 5...whose product is 30, whose difference is 1, and whose sum is 11.

5 0

3 years ago

Solve the liner system by graphing. Y=4x. x+y= -5

Darya [45]

(-1,-4) is where the equations Y=4x and x+y=-5 intersect.

3 0

3 years ago

A company surveyed 2400 men where 1248 of the men identified themselves as the primary grocery shopper in their household. a) E

polet [3.4K]

Answer:

a) With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

b) The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

c) $\alpha =1-0.98=0.02$

Step-by-step explanation:

If np' and n(1-p') are higher than 5, a confidence interval for the proportion is calculated as:

$p'-z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }\leq p\leq p'+z_{\alpha/2}\sqrt{\frac{p'(1-p')}{n} }$

Where p' is the proportion of the sample, n is the size of the sample, p is the proportion of the population and $z_{\alpha/2}$ is the z-value that let a probability of $\alpha/2$ on the right tail.

Then, a 98% confidence interval for the percentage of all males who identify themselves as the primary grocery shopper can be calculated replacing p' by 0.52, n by 2400, $\alpha$ by 0.02 and $z_{\alpha/2}$ by 2.33

Where p' and $\alpha$ are calculated as:

$p' = \frac{1248}{2400}=0.52\\\alpha =1-0.98=0.02$

So, replacing the values we get:

$0.52-2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\leq p\leq 0.52+2.33\sqrt{\frac{0.52(1-0.52)}{2400} }\\0.52-0.0238\leq p\leq 0.52+0.0238\\0.4962\leq p\leq 0.5438$

With a confidence level of 98%, the percentage of all males who identify themselves as the primary grocery shopper are between 0.4962 and 0.5438.

The lower limit of the confidence interval is higher that 0.43, so if he conduct a hypothesis test, he will find that the data shows evidence to said that the fraction is higher than 43%.

Finally, the level of significance is the probability to reject the null hypothesis given that the null hypothesis is true. It is also the complement of the level of confidence. So, if we create a 98% confidence interval, the level of confidence $1-\alpha$ is equal to 98%

It means the the level of significance $\alpha$ is:

$\alpha =1-0.98=0.02$

4 0

3 years ago