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Westkost [7]
3 years ago
15

Please help this is the last question and determines wether I pass or not

Mathematics
1 answer:
givi [52]3 years ago
3 0
Hopefully I’m not too late, but here’s how I solved it. Basically, replace F with 68. Subtract 32 from both sides so your equation becomes 9/5C=36. Divide both sides by 9/5 so C is left but itself (C=36/1.8). The answer should come out to 20. If you want to check my answer, plug 20 into the equation. Multiply 20x9/5 which equals 36. Add 36 and 32 together to get 68. Hope this helps
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Good at graphing coordinates? I need some help on that please!
ohaa [14]
Here are the coordinates :)

4 0
3 years ago
select all equations that have x = 3 as a solution. A. X + 7 = 10 B. 3+ x = 3 C. x • 3 = 1 D. 4 • x = 12 ​
castortr0y [4]

Answer:

A.

Step-by-step explanation:

7+3=10 so it will be A, you're welocme

7 0
3 years ago
Read 2 more answers
How do you factor these?
valina [46]
Hi there!

24. 6x² + 19x + 3
      1                 3    multiply 6 × 3 = 18
      6                 1    multiply 1 × 1 = 1
                               18 + 1 = 19
(x + 3)(6x + 1)

I just simply found the two factors of 6 and 3 that can add up to 19.
This way is useful when the a and c don't have much factors.


27. 5y² + 13y + 6
      1                 2    5 × 2 = 10
      5                 3    1 × 3 = 3
                               10 + 3 = 13
(x + 2)(5x + 3)


30. 16x² + 16x + 3
For this one, 16 has a lot of factors. So you can try "Grouping" method.
You multiply 16 and 3. 16 × 3 =48
Find the factors of 48 that can add up to 16.
Hmm.. 12 and 4 would be great.
Then rewrite the equation.

16x² + 12x + 4x + 3
We would factor 16x² + 12x and 4x + 3 separately. 
16x² + 12x                    4x + 3 can't be factored more.
4x(4x + 3)                     1(4x + 3)
(4x + 1)(4x + 3)


So your answers are....
24. (x + 3)(6x + 1)

27. (x + 2)(5x + 3)

30. (4x + 1)(4x + 3)
 

Hope this helped!!
6 0
4 years ago
Determine two pairs of polar coordinates for (3,-3) when 0
Xelga [282]

The two pairs of polar coordinates for the given point (3, -3) with 0° ≤ θ < 360° are (3√2, 135°) and (3√2, 315°).

<h3>What is a polar coordinate?</h3>

A polar coordinate is a two-dimensional coordinate system, wherein each point on a plane is typically determined by a distance (r) from the pole (origin) and an angle (θ) from a reference direction (polar axis).

Next, we would determine the distance (r) and angle (θ) as follows:

r = √(3² + (-3)²)

r = √(9 + 9)

r = 3√2.

θ = tan⁻¹(-3/3)

θ = tan⁻¹(-1)

θ = 3π and 7π/4 (second and fourth quadrants).

Converting to degrees, we have:

θ = 135° and 315°.

Read more on polar coordinates here: brainly.com/question/3875211

#SPJ1

Complete Question:

Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°

5 0
2 years ago
1. All of the following are true except B. A. A random variable represents a numerical value assigned to an outcome of a probabi
kolezko [41]

Answer:

The true statements are :

A. A random variable is a numerical description of the outcome of a statistical experiment.

B. In most​ applications, discrete random variables represent counted​ data.

C. In most applications, continuous random variables represent measured data.

Step-by-step explanation:

It is true statement that,

A. A random variable is a numerical description of the outcome of a statistical experiment.

B. In most​ applications, discrete random variables represent counted​ data.

C. In most applications, continuous random variables represent measured data.

The false statement is -

D. The expected value of a discrete random variable is equal to the standard deviation of the random variable.

Reason -

The mean value, or expected value, of a discrete random variable X is given by the following equation:

μ = E(x) = ∑ x p(x)

And

The variance of a discrete random variable is given by the following formula:

σ²=∑ (x−μ)² P(x)

And

The square root of the variance, or, in other words, the square root of σ², is the standard deviation of a discrete random variable :

σ = √σ²

6 0
3 years ago
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