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mamaluj [8]
2 years ago
15

What is the area of a rectangle with a length of 7 feet and a width of 3 ¾ feet?

Mathematics
2 answers:
Citrus2011 [14]2 years ago
7 0

Answer:

105/4 ft^2

Step-by-step explanation:

Multiply length and width: 7*15/4 = 105/4 ft^2

DanielleElmas [232]2 years ago
3 0
26.25 (7x3.75=26.25)
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I'm assuming you meant does y=12x pass through those coordinates, and if that's the case, then the answer is no. 

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Tan 1° + tan 2° + tan 3° +........+ tan 90°=?​
Paha777 [63]

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6 0
3 years ago
"Find y". I got this wrong and want to understand why and how to do the problem. Can someone please help?
podryga [215]

Answer:

y=\frac{15\sqrt{3} }{4}

Step-by-step explanation:

Well what you have here are two right triangles within another right triangles created by an altitude. This results in 3 similar triangles (see attached for reference)

As a result , using the properties of similar triangles, and taking ratios of their sides of the medium triangle and the largest triangle, we can form the following relationship:

\frac{b}{z}=\frac{y}{x} = \frac{z}{a+b}  (we know that a+b = 15), hence the equation becomes:

\frac{b}{z}=\frac{y}{x} = \frac{z}{15}  ----------eq 1

If we consider the largest triangle, we will see that

cos 30° = z / 15

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z = (15√3) / 2 --------eq 2

from the same largest triangle, we will also see that

sin 30° = x / 15

similarly from our special angles, we know that sin 30° = 1/2

hence,

1/2 = x/15

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now that we have values for x and z, we can neglect the first term of equation 1 and form an equality with x, y and z

\frac{y}{x} = \frac{z}{15}

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y=\frac{15\sqrt{3} }{4}

8 0
3 years ago
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