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2 years ago

Llin0374 avatar

Mathematics

2 answers:

postnew [5]2 years ago

3 0

Just saw somebody send that thanks for the announcement

Allushta [10]2 years ago

3 0

Answer:

I've seen like 5 of them saying "for new _____ go to that...

Step-by-step explanation:

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write the standard form of the equation of the line described. through (-2,3), perpendicular to y=2/7x+5

Setler79 [48]

The general form of a linear equation is
y = mx + b
where m = slope and b = y-intercept
Here m = 2/7
To get to its perpendicular equation, first the slope should be negative reciprocal. So the perpendicular slope is m = -7/2
Given the point (-2,3), use the point-slope form equation, that is
y - y1 = m(x - x1)
Plug in
y - 3 = (-7/2)[x - (-2)]
y - 3 = (-7/2)x - 7
y = (-7/2)x - 7 + 3
y = (-7/2)x - 4
That is the equation required.

4 0

3 years ago

Simplify: <br>{(12)^1 + (13)^-1}/[(1/5)^-2 × {(1/5)^-1 + (1/8)^-1}^-1]

CaHeK987 [17]

Step-by-step explanation:

$\underline{\underline{\sf{➤\:\:Solution}}}$

$\sf \dashrightarrow \: \dfrac{ \left(\left(12 \right)^{ - 1} + \left(13 \right)^{ - 1} \right) }{\left( \dfrac{1}{5}\right) ^{ - 2} \times\left( \left( \dfrac{1}{5} \right) ^{ - 1} +\left( \dfrac{1}{8} \right) ^{ - 1} \right) ^{ - 1}}$

$\sf \dashrightarrow \: \dfrac{ \left(\dfrac{1}{12} + \dfrac{1}{13} \right) }{\left( \dfrac{5}{1}\right) ^{ 2} \times\left( \dfrac{5}{1} + \dfrac{8}{1} \right) ^{ - 1}}$

LCM of 12 and 13 is 156

$\sf \dashrightarrow \: \dfrac{ \left(\dfrac{1 \times 13 = 13}{12 \times 13 = 156} + \dfrac{1 \times 12 = 12}{13 \times 12 = 156} \right) }{\ \dfrac{25}{1} \times\left( \dfrac{5 + 8}{1} \right) ^{ - 1}}$

$\sf \dashrightarrow \: \dfrac{ \left(\dfrac{13}{156} + \dfrac{12}{156} \right) }{\ \dfrac{25}{1} \times\left( \dfrac{13}{1} \right) ^{ - 1}}$

$\sf \dashrightarrow \: \dfrac{ \left(\dfrac{13 + 12}{156} \right) }{\ \dfrac{25}{1} \times\dfrac{1}{13} }$

$\sf \dashrightarrow \: \dfrac{25}{156} \div \dfrac{25}{13}$

$\sf \dashrightarrow \: \dfrac{ \cancel{25}}{156} \times \dfrac{13}{ \cancel{25} }$

$\sf \dashrightarrow \: \dfrac{13}{156}$

$\sf \dashrightarrow \: \dfrac{1}{12}$

$\sf \dashrightarrow \: Answer = \underline{\boxed{ \sf{ \dfrac{1}{12} }}}$

━━━━━━━━━━━━━━━━━━━━━━━━

$\underline{\underline{\sf{★\:\:Laws\:of\: Exponents :}}}$

$\sf \: 1^{st} \: Law = \bigg( \dfrac{m}{n} \bigg)^{a} \times \bigg( \dfrac{m}{n} \bigg)^{b} = \bigg( \dfrac{m}{n} \bigg)^{a + b}$

$\sf 2^{nd} \: Law =$

$\sf Case : (i) \: if \: a > b \: then, \bigg( \dfrac{m}{n}\bigg) ^{a} \div \bigg( \dfrac{m}{n}\bigg)^{b} = \bigg( \dfrac{m}{n}\bigg)^{a - b}$

$\sf Case : (ii) \: if \: a < b \: then, \bigg( \dfrac{m}{n}\bigg) ^{a} \div \bigg( \dfrac{m}{n}\bigg)^{b} = \dfrac{1}{\bigg( \dfrac{m}{n}\bigg)^{b - a}}$

$\sf \: 3^{rd} \: Law = \bigg\{ \bigg( \dfrac{m}{n} \bigg)^{a} \bigg\}^{b} = \bigg( \dfrac{m}{n} \bigg)^{a \times b} =\bigg( \dfrac{m}{n} \bigg)^{ab}$

$\sf \: 4^{th} \: Law = \bigg( \dfrac{m}{n} \bigg)^{ - 1} = \bigg( \dfrac{n}{m} \bigg) =\dfrac{n}{m}$

$\sf \: 5^{th} \: Law = \bigg( \dfrac{m}{n} \bigg)^{0} = 1$

3 0

2 years ago

Read 2 more answers

What number gives a result of −8 when 11 is subtracted from the quotient of the number and 6?

natima [27]

It is thirteen because you have to add to 6 till you get eleven and you go up 8 more and then you subtract it all and get your answer

4 0

3 years ago

I’ll mark u as brainlist if u get this right!!

WITCHER [35]

Answer:

Step-by-step explanation:

When X is less than -1, positive parabola.

6 0

2 years ago

Read 2 more answers

Simplify:<br> {[(16 ÷ 4) × (2 × 6)] ÷ 6} + 4 =

borishaifa [10]

Answer:

Step-by-step explanation:

divided 16 by 4 which is 4. then multiply 2 by 6, which is 12. then multiply 4 by 12. Remember to always do ( ) first. 4 by 12 is 48. Then do 48 divided by 6 which is 8. then add 8+4 which is 12.

4 0

3 years ago