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Mathematics

1 answer:

lozanna [386]3 years ago

7 0

Answer:

6x =48 for number A

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Please help need 100

stiks02 [169]

$\angle EFG\ \text{is supplementary to}\ \angle DBC\ \text{and}\\\\\angle ABC\ \text{is supplementary to}\ \angle DBC\ \text{therefore}\ m\angle EFG=m\angle ABC$

$18x+28+7x+27=180\\\\25x+55=180\ \ \ |-55\\\\25x=125\ \ \ \ |:25\\\\x=5\\\\m\angle EFG=(18x+28)^o=(18\cdot5+28)^o=118^o$

$\text{Answer: A)}\ 118^o$

4 0

4 years ago

Read 2 more answers

Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). A new versio

stich3 [128]

Answer:

12.92%

Step-by-step explanation:

Mean of the scores= u = 500

Standard deviation = $\sigma$ = 10.6

We have to find what proportion of students scored more than 512 marks.

The distribution of scores in a test generally follows the Normal distribution. So we can assume that the distribution of MCAT scores is normally distributed about the mean.

Since, the distribution is normal, we can use the concept of z scores to find the proportion of students who scored above 512.

The formula for z scores is:

$z=\frac{x-u}{\sigma}$

So, z score for x = 512 will be:

$z=\frac{512-500}{10.6}=1.13$

Thus,

P(X > 512) is equivalent to P(z > 1.13)

So, the test scores of 512 is equivalent to a z score of 1.13. Using the z table we have to find the proportion of z scores being greater than 1.13, which comes out to be 0.1292

Since,

P(X > 512) = P(z > 1.13)

We can conclude that, the proportion of students taking the MCAT who had a score over 512 is 0.1292 or 12.92%

5 0

4 years ago

a solid is composed of a cylinder with hemisherical ends. If the length of the whole solid is 108 cm and the diameter of the cyl

Lerok [7]

First work out the surface area of the solid

Area of cylindrical part:-

length of this part = 108 - 2*18 = 72 so its area

= 2 * pi * r * 72

= 2 *pi* 18 * 72 = 8143.01 cm^2

Area of the 2 hemispheres = 4 pi * 18^2 = 4071.50 cm^2

Total surface area of the solid = 12,214.51 cm^2

Cost of polishing = 12,214.51 * 7 = 85,501.58 paise

5 0

3 years ago

Diagonals of parallelograms<br><br> Solve for x

Lunna [17]

Diagonals bisect each other

$\\ \bull\tt\longmapsto 2x+10=3x$