Does 2 go into 15 and also does 2 go into 9?

Please help i have to turn in in 8 mins....thanks :)

pychu [463]

6√3

Step-by-step explanation:

6 is x. side across from right angle (12) is 2x. so 6x2 to get 12. missing side is x√3. so 6√3

6 0

3 years ago

Read 2 more answers

What are the surface area and volume of the following shape?

steposvetlana [31]

Answer:

Volume : 23.6ft

Cubic Yards: 0.9ft

Surface area: 20.5ft

Squared yards: 5ft

Step-by-step explanation:

3 0

3 years ago

There are 47 numbers Find the probability that i will pick the 6 winning numbers in a draw

Agata [3.3K]

Answer: You have six numbers on your ticket. In drawing the first number from the collection of 45, one of those six numbers must be drawn in order for you to still have a chance of winning the big prize. So following the draw, the probability is only 6/45 (or 1/9) that you’re still in the game.

You can now see that on each successive draw the probability steadily drops- to 5/44, 4/43, 3/42, 2/41, and for the last number 1/40. As other answers have stated, there are 8,145,060 possible draws of six numbers and only one makes you a winner.

If you bought ten tickets for every drawing, the odds reach a 50% chance of having won at about 520,550 drawings. Assuming two drawings per week, the chance of winning reaches 50% in about 5,200 years.

Of course, SOMEONE will win and if you don’t play, your chance of winning is zero. It’s kind of fun to occasionally buy lottery tickets just for the dream of winning but don’t spend a lot of money on them.

5.9K viewsView upvotes · Answer requested by Arthur C. Thorpe

7

Related Questions (More Answers Below)

Step-by-step explanation:

3 0

3 years ago

Using The exterior angle Theorem solve for the identified angle

Lerok [7]

Answer:

107

Step-by-step explanation:

180-(65+42) = SQR = 73

180-73 = 107

8 0

3 years ago

The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter

Natasha2012 [34]

Answer:

$(1\frac{1}{2},1)$ - False

$(4,6)$ - True

$(18,12)$ -- False

$(0,0)$ -- True

$(2\frac{1}{2},3\frac{3}{4})$ -- True

Step-by-step explanation:

The points are

$(1\frac{1}{2},1)$ , $(4,6)$ , $(18,12)$ , $(0,0)$ and $(2\frac{1}{2},3\frac{3}{4})$ ---- missing from the question

Given

$y = 1\frac{1}{2}x$

Required

Determine if each of the points would be on $y = 1\frac{1}{2}x$

To do this, we simply substitute the value of x and of each point in $y = 1\frac{1}{2}x$ .

(a) $(1\frac{1}{2},1)$

In this case;

$x = 1\frac{1}{2}$ and $y = 1$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 1\frac{1}{2}$

$y = \frac{3}{2} * \frac{3}{2}$

$y = \frac{9}{4}$

$y = 2\frac{1}{4}$

The point $(1\frac{1}{2},1)$ won't be on the graph because the corresponding value of y for $x = 1\frac{1}{2}$ is $y = 2\frac{1}{4}$

(b) $(4,6)$

In this case;

$x = 4$

$y = 6$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 4$

$y = \frac{3}{2} * 4$

$y = \frac{3* 4}{2}$

$y = \frac{12}{2}$

$y = 6$

The point $(4,6)$ would be on the graph because the corresponding value of y for $x = 4$ is $y = 6$

(c) $(18,12)$

In this case:

$x = 18;y = 12$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 18$

$y = \frac{3}{2} * 18$

$y = \frac{3* 18}{2}$

$y = \frac{54}{2}$

$y = 27$

The point $(18,12)$ wouldn't be on the graph because the corresponding value of y for $x = 18$ is $y = 12$

(d) $(0,0)$

In this case;

$x =0; y = 0$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 0$

$y = 0$

The point $(0,0)$ would be on the graph because the corresponding value of y for $x = 0$ is $y = 0$

(e) $(2\frac{1}{2},3\frac{3}{4})$

In this case:

$x = 2\frac{1}{2}$ ; $y = 3\frac{3}{4}$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 2\frac{1}{2}$

$y = \frac{3}{2} * \frac{5}{2}$

$y = \frac{15}{4}$

$y = 3\frac{3}{4}$

The point $(2\frac{1}{2},3\frac{3}{4})$ would be on the graph because the corresponding value of y for $x = 2\frac{1}{2}$ is $y = 3\frac{3}{4}$

3 0

3 years ago