The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
<h3>
What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
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I'm assuming your function is f(x) = -9^(x+1)
So we just have to plug in and see if the function is true.
1) -9^(0+1) = -9^1 = -9
YES
2) -9^(1+1) = -9^2 = -81
NO
3) -9^(-1+1) = -9^0 = -1
YES
Answer:
The atomic weight (or atomic mass) of Vanadium is 50.9415 which means that a "mole" of Vanadium atoms (6.02 x 10^23 atoms) will have a mass of 50.9415 grams. So, 214.1 grams of Vanadium would have
(214.1 / 50.9415) * (6.02 x 10^23) = 2.530 x 10^24 atoms
Step-by-step explanation:
Tim spends 1/3 each weekday sleeping and 7/24 in school. We can write 1/3 as 8/24 so we have a common denominator. Now we can see that Tim sleeps for 1/24 time of a weekday more then he spends in school.
I hope that's what you meant.
Answer: y=-7
Step-by-step explanation: on why axis and is pallet yo x axis
