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3 years ago

On a recent survey, 60% of those surveyed indicated that they preferred walking to running.

Mathematics

1 answer:

Montano1993 [528]3 years ago

3 0

Answer:

324 people, C

Step-by-step explanation:

You first make 60 percent a decimal by moving the deciaml point up two digits, which makjes the number .60. Then, multiply 540 x .60 which gets your 324.

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The load L, in pounds, of a wheelbarrow is the sum of its own 42-lb weight and the weight of the bricks that it carries as shown

sladkih [1.3K]

L= 4*B+42
L= the load
B is the weight of each brick
42 is the weight of the carrier

5 0

3 years ago

Select all the points that are on the line through LaTeX: (0,5)( 0 , 5 ) and LaTeX: (2,8)( 2 , 8 ). Group of answer choices LaTe

Ivenika [448]

Answer:

The points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

Step-by-step explanation:

The equation of the line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

So, the equation of the line passing through two points (0,5) and ( 2, 8 ) is

$y-5=\frac{8-5}{2-0}(x-0)$

$\Rightarrow y=1.5x+5\cdots(i)$

For the point (4,11), pout x=4 in equation (i), we have

$y=1.5\times4 +5=11$ , which is given y coordinate, hence this point (4,11) lies on the line.

For the point (5,10), pout x=5 in equation (i), we have

$y=1.5\times5 +5=12.5,$ which is not the given y coordinate, hence the point (5,10) doesn't lie on the line.

For the point (6,14), pout x=6 in equation (i), we have

$y=1.5\times6 +5=14$ , which is the given y coordinate, hence the point (6,14) lies on the line.

For the point (30,50), pout x=30 in equation (i), we have

$y=1.5\times30 +5=50$ , which is the given y coordinate, hence the point (30,50) lies on the line.

For the point (40,60), pout x=40 in equation (i), we have

$y=1.5\times40 +5=65$ , which is not the given y coordinate, hence the point (40,60) doesn't lie on the line.

Hence, the points (4,11), (6,14), (30,50) lie on the line joining the points (0,5) and (2,8).

4 0

3 years ago

C is the center of the circle. Find the area of the segment shown in the figure,

Semmy [17]

Answer: A 28.50 sq. u

Step-by-step explanation:

In the given figure , radius of the circle : r= 10 u

Central angle made by Arc ED: $\theta$ = 90° ( right angle )

Now , the area of the segment is given by :-

Area of segment = Area of sector (ECD) - Area of triangle(ECD) (i)

Formula : Area of right triangle = 0.5 x Base x Height

Area of sector = $\dfrac{\theta}{360^{\circ}}\times\pi r^2$

Using above formulas in (i) and substituting corresponding values , we get

Area of segment =

$\dfrac{90^{\circ}}{360^{\circ}}\times\pi (10)^2-0.5\times10\times10\\\\=\frac{1}{4}(3.14)(100)-50\\\\=78.5-50=28.5\ sq.u$

Hence, the correct answer is A 28.50 sq. u

6 0

3 years ago

How do you write 4/5 as a percentage? lol i know this is simple but im so... help

adoni [48]

Answer:

85%

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Y=x +3 1 23x+2y=-4 what is it

erik [133]

Answer:

x=-0.08 and y=2.92

Step-by-step explanation:

123x + 2(x+3) = -4 y = -0.08 + 3

123x + 2x + 6 = -4 = 2.92

125x + 6 = -4

125x = -10

x= -0.08

5 0

3 years ago