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liq [111]
3 years ago
8

The prime factor decomposition of

Mathematics
1 answer:
AnnyKZ [126]3 years ago
6 0

Answer:

265?? i am confuse but ok

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Can someone help me out my grade are bad
hjlf

Answer:

A. The first 2 are equivalent expressions.

B. The last 2 are equavalent expressions.

3 0
3 years ago
Read 2 more answers
Which expression is equivalent to StartFraction (3 m Superscript negative 1 Baseline n squared) Superscript negative 4 Baseline
koban [17]

Answer:

3m^{10}n^{-11}

Step-by-step explanation:

Given the expression \frac{(3m^{-1}n^{2})^{-4}   }{(2m^{-2}n)^{3}  }, we will use laws of indices to get the equivalent expression as shown below;

According to one of the law of indices,

\frac{a^{m} }{a^{n} } = a^{m-n}  \ and\ (a^{m})^{n} = a^{mn}

\frac{(3m^{-1}n^{2})^{-4}   }{(2m^{-2}n)^{3}  }\\= \frac{3m^{4}n^{-8}   }{2m^{-6}n^{3}  }\\= 3m^{(4-(-6))} * n^{-8-3}\\ = 3m^{10}n^{-11}

This gives the required expression

8 0
3 years ago
Read 2 more answers
What is the solution to –2|2.2x – 3.3| = –6.6? x = –3 x = 3 x = –3 or x = 0 x = 0 or x = 3
Nonamiya [84]

x = 3

-2 | 2.2(3) -3.3 | = -6.6

-2 | 6.6 - 3.3 | = -6.6

-2 | 3.3 | = -6.6

-2 * 3.3 = -6.6

-6.6 = -6.6

6 0
3 years ago
Read 2 more answers
15 cm<br> 16 cm<br> Part 1: Find the radius of the cone. (2 points)
zvonat [6]

formula=1/3 x 3.14 x r^2 x height

=16 is diameter so radius will be 16/2 or 8

<em>:</em><em>let </em><em>put </em><em>terms </em><em>in </em><em>the </em><em>formula:</em>

1/3 x 3.14. x 8^2 x 15 = <em><u>1</u></em><em><u>0</u></em><em><u>0</u></em><em><u>4</u></em><em><u>.</u></em><em><u>8</u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em>

<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em>volume=</em><em>1</em><em>0</em><em>0</em><em>4</em><em>.</em><em>8</em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em>

5 0
3 years ago
Use completing the square to solve this quadratic equation.
borishaifa [10]

Step-by-step explanation:

x² + 6x + 9 = 2

(x + 3)² = 2

x + 3 = ±sqrt(2)

x = -3 ± sqrt(2)

so, B and D are correct.

control :

(-3 + sqrt(2))² + 6(-3 + sqrt(2)) + 9 = 2

9 + 2 - 6sqrt(2) - 18 + 6sqrt(2) + 9 = 2

2 = 2

correct

(-3 - sqrt(2))² + 6(-3 - sqrt(2)) + 9 = 2

9 + 2 + 6sqrt(2) - 18 - 6sqrt(2) + 9 = 2

2 = 2

correct

(3 + sqrt(2))² + 6(3 + sqrt(2)) + 9 = 2

9 + 2 + 6sqrt(2) + 18 + 6sqrt(2) + 9 = 2

38 + 12sqrt(2) = 2

wrong.

(3 - sqrt(2))² + 6(3 - sqrt(2)) + 9 = 2

9 + 2 - 6sqrt(2) + 18 - 6sqrt(2) + 9 = 2

38 - 12sqrt(2) = 2

wrong.

7 0
3 years ago
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