Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
#SPJ1
Given:
Endpoints of segment AB are A(- 18, 5) and B(- 4, 5).
Point Z is located exactly 1/8 of the distance from A to B.
To find:
The value of the x-coordinate of point Z.
Solution:
Point Z is located exactly 1/8 of the distance from A to B.
AZ:AB=1:8
AZ:ZB = AZ:(AB-AZ)= 1:(8-1) = 1:7
It means point Z divided segment AB in 1:7.
Using section formula, the x coordinate of point Z is
![x-coordinate=\dfrac{mx_2+nx_1}{m+n}](https://tex.z-dn.net/?f=x-coordinate%3D%5Cdfrac%7Bmx_2%2Bnx_1%7D%7Bm%2Bn%7D)
![x-coordinate=\dfrac{1(-4)+7(-18)}{1+7}](https://tex.z-dn.net/?f=x-coordinate%3D%5Cdfrac%7B1%28-4%29%2B7%28-18%29%7D%7B1%2B7%7D)
![x-coordinate=\dfrac{-4-126}{8}](https://tex.z-dn.net/?f=x-coordinate%3D%5Cdfrac%7B-4-126%7D%7B8%7D)
![x-coordinate=\dfrac{-130}{8}](https://tex.z-dn.net/?f=x-coordinate%3D%5Cdfrac%7B-130%7D%7B8%7D)
![x-coordinate=-16.25](https://tex.z-dn.net/?f=x-coordinate%3D-16.25)
Therefore, the required x-coordinate of point Z is -16.25.
Answer:
is this science?
Step-by-step explanation:
I need a picture so that I could see the diagram