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3 years ago

Why would a user want to resend a message? Check all that apply.

Computers and Technology

2 answers:

PtichkaEL [24]3 years ago

6 0

Answer:

He's right its A, B, D and E

Explanation:

Dmitrij [34]3 years ago

5 0

Answer:

Explanation:

O to include new recipients

D to include a forgotten attachment

D to respond to a request from a recipient who accidentally deleted it

O to include missing information

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What information on social networking sites could be used to discriminate against a potential employee

NISA [10]

the answer on plato is b

political affiliations

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3 years ago

What paper should I use for technical drawing?

Vitek1552 [10]

Answer:

classic A4 format, and therefore for 210 x 297 mm sheets

7 0

3 years ago

def getCharacterForward(char, key): """ Given a character char, and an integer key, the function shifts char forward `key` steps

zhenek [66]

Answer:

def getCharacterForward(char, key):
charList = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
if(len(char) > 1):
return None
elif(not isinstance(key, int)):
return -1
else:
index = charList.find(char)
if(index + key <= 25):
return charList[index + key]
else:
return charList[(index + key)% 26]
print(getCharacterForward("C", 4))
print(getCharacterForward("X", 4))

Explanation:

Firstly, define a charList that includes all uppercase alphabets (Line 2). We presume this program will only handle uppercase characters.

Follow the question requirement and define necessary input validation such as checking if the char is a single character (Line 4). We can do the validation by checking if the length of the char is more than 1, if so, this is not a single character and should return None (Line 5). Next, validate the key by using isinstance function to see if this is an integer. If this is not an integer return -1 (Line 6 - 7).

Otherwise, the program will proceed to find the index of char in the charList using find method (Line 9). Next, we can add the key to index and use the result value to get forwarded character from the charList and return it as output (Line 11).

However, we need to deal a situation that the char is found at close end of the charList and the forward key steps will be out of range of alphabet list. For example the char is X and the key is 4, the four steps forward will result in out of range error. To handle this situation, we can move the last two forward steps from the starting point of the charList. So X move forward 4 will become B. We can implement this logic by having index + key modulus by 26 (Line 13).

We can test the function will passing two sample set of arguments (Line 15 - 16) and we shall get the output as follows:

8 0

3 years ago

Will robots take people's jobs? write in complete sentence.

lilavasa [31]

Answer:

yes

Explanation:

yes because they already have them for old gun ships (which they still use) and they have made cars with them and more including bombing situations IED detinators they used in Afghanistan and in Iraq in 2011.

6 0

3 years ago

1. Write a static method named computeOddSum that is passed an array of int's named numbers. The method must compute and return

S_A_V [24]

Answer:

The method in Java is as follows:

public static int computeOddSum(int [] myarray){

int oddsum = 0;

for(int i=0; i<myarray.length; i++ ) {

if(myarray[i]%2==1) {

oddsum+=myarray[i];

}

return oddsum;

}

Explanation:

This defines the static method

public static int computeOddSum(int [] myarray){

This initializes oddsum to 0

int oddsum = 0;

This iterates through the array

for(int i=0; i<myarray.length; i++ ) {

This checks for odd number

if(myarray[i]%2==1) {

The odd numbers are added, here

oddsum+=myarray[i];

}

This returns the calculated sum of odd numbers

return oddsum;

}

To call the method from main, use:

int [] myarray = {3, 10, 11, 2, 6, 9, 5};

System.out.println("Odd sum = " + computeOddSum(myarray));

5 0

3 years ago