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2 years ago

What types of things were often NOT captured in early photographs?

1 answer:

4 0

Answer: Here's the answer: How to Identify 5 Types of Old Photographs 1 Daguerreotype (1840’s – early 1860) 2 Ambrotypes (1855-1865) 3 Tintypes (1856-1890’s) 4 Cartes des Visites (Introduced in 1859) 5 Cabinet Cards (1860-Early 1900’s)

Explanation: Pls mark me the brainiest and yw

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Denise is working as a market analyst in a publishing house. What is her career field?

e-lub [12.9K]

Cynthia career field would be a office job such as assisting a CEO or leader of a company.

8 0

3 years ago

Read 2 more answers

Which of the following statements is true of subroutines? Check all that apply.

erica [24]

I believe it’s the first answer

“They can be used in multiple places “

But I’m not sure!!

6 0

3 years ago

Read 2 more answers

Design a TestScores class that has fields to hold three test scores. The class should have a constructor, accessor and mutator m

sweet-ann [11.9K]

Answer:

Answered below

Explanation:

class TestScores {

double test1;

double test2;

double test 3;

public TestScores (double test1, double test2, double teat3){

this.test1= test1;

this.test2 = test2;

this.test3 = teat3;}

//mutator

public setTest1(double test1){

this.test1 = test1;

}

//accessor

public double getTest1(){

return test 1;

}

//Write same accessors and mutators for test2 and test3

public double getTestAverage(){

double sum = test1+test2+test3;

return sum / 3;

}

class TestRun{

public static void main (String [] args){

TestScores scores = new TestScores(50.5, 40.0, 80.7)

int average = scores.getTestAverage();

System.out.print(average);

}

6 0

2 years ago

Why does it say error on that last line of code

wel

Answer:

i have no clue

Explanation:

8 0

3 years ago

Read 2 more answers

Suppose that TCP's current estimated values for the round trip time (estimatedRTT) and deviation in the RTT (DevRTT) are 400 mse

Masja [62]

Answer:

617.5 msecs, 580.89 msecs, 582.36 msecs

Explanation:

Lets look at the following formulas:

EstimatedRTT = α * SampleRTT+(1- α) * EstimatedRTT

DevRTT = β * | SampleRTT- EstimatedRTT|+(1- β)* DevRTT

TimeoutInterval = EstimatedRTT +4* DevRTT

Given values are:

EstimatedRTT = 400 msec

DevRTT = 25 msec

α = 0.125

β = 0.25

After the first RTT estimate: (210)

EstimatedRTT = 0.125 * 210 + (1 - 0.125) * 400 = 376.25 msecs

DevRTT = 0.25 * |210 - 376.25| + (1 - 0.25) * 25 = 60.3125 msecs

TimeoutInterval = 376.25 + 4 * 60.3125 = 617.5 msecs

After the second RTT estimate: (400)

EstimatedRTT = 0.125 * 400 + (1 - 0.125) * 376.25 = 379.218 msecs

DevRTT = 0.25 * |400 - 379.218| + (1 - 0.25) * 60.3125 = 50.42 msecs

TimeoutInterval = 379.218 + 4 * 50.42 = 580.89 msecs

After the third RTT estimate: (310)

EstimatedRTT = 0.125 * 310 + (1 - 0.125) * 379.218 = 370.56 msecs

DevRTT = 0.25 * |310 - 370.56| + (1 - 0.25) * 50.42 = 52.95 msecs

TimeoutInterval = 370.56 + 4 * 52.95 = 582.36 msecs

5 0

3 years ago