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3 years ago

What happens to the frequency as the period of a sinusoidal function increases

Mathematics

2 answers:

konstantin123 [22]3 years ago

5 0

Increases I’m sure if it’s not right let me know because I think it is if not it’s c

KIM [24]3 years ago

5 0

It should be c because the relationship between the frequency and the function matters.

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Jocelyn calculates that see will take 105 minutes to run 7 miles. She runs the distance in 84 minutes. What is Jillian’s percent

VladimirAG [237]

Answer:

$25%$ %

Step-by-step explanation:

Given: Jocelyn calculates that see will take 105 minutes to run 7 miles. She runs the distance in 84 minutes.

To find: Jillian’s percent error

Solution:

Actual time taken by Jocelyn to run 7 miles = 84 minutes

Approximate time taken by Jocelyn to run 7 miles = 105 minutes

Error = $|105-84|=21$ minutes

Percent error = error/(Actual time taken) × (100) = $\frac{21}{84}(100)=25\%$

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3 years ago

What's the area of the green highlighted face shown below??

GrogVix [38]

Answer:

45.5 ft sqaured

Step-by-step explanation:

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3 years ago

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8_murik_8 [283]

Answer:

Step-by-step explanation:

bc i said so

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3 years ago

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Some one help me please I don’t understand this

3241004551 [841]

Y = log3 27

27 = 3^x

3^3 = 27

so x = 3

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3 years ago

What are the coordinates of the x-intercepts of the parabola y = x² - 8x + 15?

tamaranim1 [39]

Answer:

(3, 0) and (5, 0)

Step-by-step explanation:

we have

$y=x^{2}-8x+15$

we know that

The x-intercepts are the values of x when the value of y is equal to zero

For y=0

$x^{2}-8x+15=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2}-8x+15=0$

$a=1\\b=-8\\c=15$

substitute in the formula

$x=\frac{-(-8)\pm\sqrt{-8^{2}-4(1)(15)}} {2(1)}$

$x=\frac{8\pm\sqrt{4}} {2}$

$x=\frac{8\pm2} {2}$

$x=\frac{8+2} {2}=5$

$x=\frac{8-2} {2}=3$

x=3, x=5

therefore

The x-intercepts are (3,0) and (5,0)

4 0

3 years ago