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3 years ago

Complete the proof. PROVE:△VWY≅△UXY

Mathematics

2 answers:

svetoff [14.1K]3 years ago

8 0

Answer:

<h3>D.) SAS or Side angle Side</h3>

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stiv31 [10]3 years ago

8 0

Yes ma’am I am sorry to say yes ma’am I will be back home soon I love it I hope it gets

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Consider the function on the interval (0, 2π). f(x) = 7 sin2(x) + 7 sin(x) (a) Find the open interval(s) on which the function i

-BARSIC- [3]

Answer with Step-by-step explanation:

Given

$f(x)=7sin(2x)+7sin(x)$

Differentiating both sides by 'x' we get

$14cos(2x)+7cos(x)=f'(x)$

Now we know that for an increasing function we have

$f'(x)>0\\\\14cos(2x)+7cos(x)>0\\\\2cos(2x)+cos(x)>0\\\\2(2cos^{2}(x)-1)+cos(x)>0\\\\4cos^{2}(x)+cos(x)-2>0\\\\(2cos(x)+\frac{1}{2})^2-2-\frac{1}{4}>0\\\\(2cos(x)+\frac{1}{2})^2>\frac{9}{4}\\\\2cos(x)>\frac{3}{2}-\frac{1}{2}\\\\\therefore cos(x)>\frac{1}{4}\\\\\therefore x=[0,cos^{-1}(1/4)]\cup [2\pi-cos^{-1}(1/4),2\pi ]$

Similarly for decreasing function we have

$[tex]f'(x)$

Part b)

To find the extreme points we equate the derivative with 0

$f'(x)=0\\\\cos(x)=\frac{1}{4}\\\\x=cos^{-1}(\frac{1}{4})$

Thus point of extrema is only 1.

4 0

4 years ago

Multiply: 3m3(2m2 + 3m − 1) 6m6 + 6m4 15m6 − 9m3 6m5 + 9m3 − 3m3 6m5 + 9m4 − 3m3

nalin [4]

Step-by-step explanation:

hope this helps you out

3 0

3 years ago

Stuck on these two shapes <br>need help in working out the surface area

ArbitrLikvidat [17]

Answer:

Part 1) The surface area of the triangular prism is $SA=660\ cm^{2}$

Part 2) The surface area of the trapezoidal prism is $SA=2,864\ cm^{2}$

Step-by-step explanation:

Part 1) Find the surface area of the triangular prism

we know that

The surface area is equal to

$SA=2B+PL$

where

B is the area of the triangular base of the prism

P is the perimeter of the base of the prism

L is the length of the prism

<u>Find the area of the triangular base B</u>

$B=\frac{1}{2}(10)(12)=60\ cm^{2}$

<u>Find the perimeter of the base P</u>

$P=10+13+13=36\ cm$

$L=15\ cm$

substitute the values

$SA=2(60)+(36)(15)=660\ cm^{2}$

Part 2) Find the surface area of the trapezoidal prism

we know that

The surface area is equal to

$SA=2B+PL$

where

B is the area of the trapezoid base of the prism

P is the perimeter of the base of the prism

L is the length of the prism

<u>Find the area of the trapezoid base B</u>

$B=\frac{1}{2}(28+15)(8)=172\ cm^{2}$

<u>Find the perimeter of the base P</u>

$P=15+28+10+10=63\ cm$

$L=40\ cm$

substitute the values

$SA=2(172)+(63)(40)=2,864\ cm^{2}$

4 0

3 years ago

Only I need help with 1,2 and three please

Mazyrski [523]

Is that the whole thing?

4 0

3 years ago

-9 + 1/4x - 6 - 1/8x

Deffense [45]

Answer:

Assuming you want me to simplify your answer, the answer to your question is x/8-15.

Step-by-step explanation:

Simplify each term by combining 1/4 and x, and then combine x and 1/8 to get -9+x/4-6-x/8. Subtract 6 from -9 for x/4-15-x/8. Write x/4 as a fraction with a CD (Common Denominator) by multiplying by 2/2. Write each expression with a CD of 8. Combine the numerators, subract x from x*2 by reordering x and 2 to get 2*x-x/8-15. Then subract x from x to get x/8-15.

5 0

3 years ago

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