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kirill115 [55]
2 years ago
15

Simplify the expression 10[4x10÷(6^2-4^2)+1] A. 210 B. 30 C. 201 D. 20

Mathematics
2 answers:
tiny-mole [99]2 years ago
5 0

How to get answer by Mimiwhatsup:

Follow\:the\:PEMDAS\:order\:of\:operations\\P: Parenthesis, E- Exponents, D-Division, M-Multiplication, A - Addition, S-Subtraction\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:10\cdot \:3\::\quad 30\\=30

Aleks [24]2 years ago
4 0

Your answer is B. 30. Here's why:

First, you do the parenthesis inside the parenthesis, which is 6 to the 2nd minus 4 to the 2nd. 6^2 is 36 and 4^2 is 16, and the difference is 20. Second we have 4x10÷20+1. With Order of Operations, you get 40÷20+1, then 2+1 and lastly 3. Finally after <u>these</u> parenthesis, you multiply by the 10 on the outside and your final answer, 30.

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Answer:

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Step-by-step explanation:

The information from the word problem are;

The count of the numbers in the sum = 3 numbers

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The value of the third number = 4 × The value of the first number

The value of the first number = 10 + The value of the second

Let 'x' represent the first number, let 'y' represent the second number and let 'z' represent the third number, we have;

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x = y + 10...(3)

From equation (3), we get;

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Substituting the value of <em>z</em> from equation (2) and the value of <em>y</em> from equation (4) in equation (1) gives;

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x + (x - 10) + 4·x = x + x - 10 + 4·x = 6·x - 10 = 86

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From equation (4), we get

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