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aleksandrvk [35]

3 years ago

15

Zoey purchased a new car in 1992 for \$28,000$28,000. The value of the car has been depreciating exponentially at a constant rat

e. If the value of the car was \$9,600$9,600 in the year 1996, then what would be the predicted value of the car in the year 1998, to the nearest dollar?

2 answers:

Andreas93 [3]3 years ago

7 0

Answer:

5621

Step-by-step explanation:

elena-s [515]3 years ago

3 0

400$
Explanation:
In 1992, the price is 28000$ and 9600$ in 1996 so in 4 years the value the car lost is 18400$
Dividing 18400 by 4 years we get 4600 depreciation value per year.
Between 1996 and 1998 there is 2 years
So in 1998 the value of the car will be:
9600 (value in 1996) - 2x4600 = 400$

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Step-by-step explanation:

Part 22) Find the perimeter and area

step 1

The area of a rectangle is equal to

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we have

$L=5(a^2)(b^4)\ units$

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Remember that

When multiply exponents with the same base, adds the exponents and maintain the base

substitute in the formula

$A=(5(a^2)(b^4))(3(a)(b^2))$

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step 2

The perimeter of a rectangle is equal to

$P=2(L+W)$

we have

$L=5(a^2)(b^4)\ units$

$W=3(a)(b^2)\ units$

substitute in the formula

$P=2(5(a^2)(b^4)+3(a)(b^2))$

$P=10a^2b^4+6ab^2\ unit$

Part 24) Find the perimeter and area

step 1

The area of triangle is equal to

$A=\frac{1}{2}bh$

where

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$h=4m^2\ units$

Remember that

When multiply exponents with the same base, adds the exponents and maintain the base

substitute the given values

$A=\frac{1}{2}(8mn)(4m^2)$

$A=16m^3n\ units^2$

step 2

Find the perimeter

I will assume that is an equilateral triangle (has three equal length sides)

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$P=3b$

where

$b=8mn\ units$

substitute

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Part 26) Find the area

The area of a circle is equal to

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where

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Remember the property

$(a^{m})^{n}=a^{m*n}$

substitute in the formula the given value

$A=\pi (3x^3y)^{2}$

$A=9\pi x^6y^{2}\ units^2$

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