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aleksandrvk [35]
3 years ago
15

Zoey purchased a new car in 1992 for \$28,000$28,000. The value of the car has been depreciating exponentially at a constant rat

e. If the value of the car was \$9,600$9,600 in the year 1996, then what would be the predicted value of the car in the year 1998, to the nearest dollar?
Mathematics
2 answers:
Andreas93 [3]3 years ago
7 0

Answer:

5621

Step-by-step explanation:

elena-s [515]3 years ago
3 0
400$
Explanation:
In 1992, the price is 28000$ and 9600$ in 1996 so in 4 years the value the car lost is 18400$
Dividing 18400 by 4 years we get 4600 depreciation value per year.
Between 1996 and 1998 there is 2 years
So in 1998 the value of the car will be:
9600 (value in 1996) - 2x4600 = 400$
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Solution:

If the <u>numerator</u> and the <u>denominator</u> have like bases in exponents, then the <u>exponents</u> subtract.

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2 years ago
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3 years ago
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3 0
3 years ago
Can someone tell me how to resolve this? Please....
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6 0
3 years ago
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qwelly [4]

Answer:

180 cm²

Step-by-step explanation:

From inspection of the diagram, the surface area is made up of the area of 4 congruent triangles and the area of one square.

Area of a square = x² (where x is the length of one side)

⇒ area of the square = 6² = 36 cm²

Area of a triangle = 1/2 x base x height

⇒ area of one triangle = 1/2 x 6 x 12 = 36 cm²

Total surface area = 4 x area of one triangle + area of the square

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                               = 180 cm²

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2 years ago
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