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aleksandrvk [35]
3 years ago
15

Zoey purchased a new car in 1992 for \$28,000$28,000. The value of the car has been depreciating exponentially at a constant rat

e. If the value of the car was \$9,600$9,600 in the year 1996, then what would be the predicted value of the car in the year 1998, to the nearest dollar?
Mathematics
2 answers:
Andreas93 [3]3 years ago
7 0

Answer:

5621

Step-by-step explanation:

elena-s [515]3 years ago
3 0
400$
Explanation:
In 1992, the price is 28000$ and 9600$ in 1996 so in 4 years the value the car lost is 18400$
Dividing 18400 by 4 years we get 4600 depreciation value per year.
Between 1996 and 1998 there is 2 years
So in 1998 the value of the car will be:
9600 (value in 1996) - 2x4600 = 400$
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