Answer:
he pays $18.19 hope this helps have a nice day please give me brainliest
Step-by-step explanation:
You can subtract 78.2 from 287 to get the x value alone. Your new expression will look like this:
.5x=208.8
Next you divide by .5 (or multiply the reciprocal 1/.5 depending on how you were taught)
x=417.6
Hope that helps!!
Answer:
Approximately, the 90% confidence interval for the students' mean IQ score is between 129.045 - 130.956
Step-by-step explanation:
The formula to use to solve this question is called the Confidence Interval formula.
Confidence interval =
x ± z × ( σ/ (√n) )
Where:
x = the sample mean = 130
z = the z-value for 90% confidence = 1.645
σ = standard deviation = 7
n = sample size = 145
130 ± 1.645 × (7/√145)
130 ± 0.9562687005
130 - 0.9562687005 = 129.0437313
130 + 0.9562687005 = 130.9562687005
Therefore, approximately, the 90% confidence interval for the students' mean IQ score is between 129.045 - 130.956
Answer:
Step-by-step explanation:
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