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uranmaximum [27]
3 years ago
7

Kala finished her history assignment in 3/4 hours. Then she completed her English assignment in 1/2 hours. How much more time di

d Kala spend on her history assignment? Write your answer as a fraction in simplest form.
Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0

Answer:

1/4

Step-by-step explanation:

3/4 - 1/2 = 3/4 - 2/4 = 1/4 <===

Kala spent 1/4 of an hr ( or 15 minutes) more on her history

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person invested $3,800 in an account growing at a rate allowing the money to double every 13 years. How much money would be in t
Advocard [28]

Answer:

9922

Step-by-step explanation:

y= 3800(2) 18/13

y=9921.88890259

3 0
3 years ago
98, 64, 75, 57, 86, 60, 91, 98, 79
astraxan [27]

Answer:

The median is 79

The median of the first quartile is 62

The median of the third quartile is 94.5

The inter quartile range is 32.5

Step-by-step explanation:

The median is the middle number of arranged number from smallest to greatest

The median of the first quartile is the middle number of the numbers before the median

The median of the third quartile is the middle number of the numbers after the median

The inter quartile range is the difference of the median of the 3rd quartile and the median of the 1st quartile

The numbers are 98, 64, 75, 57, 86, 60, 91, 98, 79

Let us arrange the numbers from small to big

57, 60, 64, 75, 79, 86, 91, 98, 98

They are 9 numbers

The middle one is the 5th number (4 before it and 4 after it)

The 5th number is 79

The median is 79

The numbers before the median are 57, 60, 64, 75

They are 4 numbers

The middle numbers are 2nd and 3rd

The median is the average of them

The 2nd number is 60 and the 3rd number is 64

The median of the first quartile = \frac{60+64}{2} = 62

The median of the first quartile is 62

The numbers before the median are 86, 91, 98, 98

They are 4 numbers

The middle numbers are 2nd and 3rd

The median is the average of them

The 2nd number is 91 and the 3rd number is 98

The median of the third quartile = \frac{91+98}{2} = 94.5

The median of the third quartile is 94.5

The inter quartile range = third median - first median

First median = 62

Third median = 94.5

Inter quartile range = 94.5 - 62 = 32.5

The inter quartile range is 32.5

7 0
3 years ago
Decrease 42 by 15%.<br> it's for maths and it's decreasing percenages
sleet_krkn [62]
OK so 1st you need to do 42 times .15 = 6.3 then you need to subtract that number from 42 which is 35.7 so that is your answer! I hope it helps :) 
7 0
3 years ago
This is really hard... can anyone help..? Please no wrong answers
kifflom [539]

Answer:

13

Step-by-step explanation:

I believe I answered a similar question, the reasoning behind it is the same.

7 0
3 years ago
Evaluate the radical.<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B1000%7D%20" id="TexFormula1" title=" \sqrt[3]{100
Korvikt [17]

Answer:

3_/1000

= 10^(3×1/3)

=10^1

=10

3 0
3 years ago
Read 2 more answers
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