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3 years ago

My sister needs help!

Mathematics

2 answers:

arlik [135]3 years ago

6 0

.....................

rodikova [14]3 years ago

6 0

the answer would be 2=1/2 x +B

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What is 3.4675 rounded to the nearest hundreth

GarryVolchara [31]

Answer:

3.47

Step-by-step explanation:

the hundreth is the second place after the decimal

always round up on number 5+

6 0

4 years ago

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You made a square card. The card did not fit in the envelope so you trimmed it. You trimmed 4 inches from the length and 5 inche

ludmilkaskok [199]

Answer:

The original dimensions of the card were 9 inches length and 9 inches width

Step-by-step explanation:

Let x be the original length and width of the card in inches (remember that it was squared originally). The exercise says that the area of the new width, with dimensions x-4 and x-5 is 20 square inches, therefore

(x-4)*(x-5) = 20

x²-9x+20 = 20

x²-9x = 0

x*(x-9) = 0

x = 0 or x = 9

Since x must be positive, then it cant be 0, thus, x has to be 9. The original dimensions of the card were 9 inches length and 9 inches width.

7 0

4 years ago

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How do i solve this?

Alina [70]

Answer:

m∠R = 60°

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] SOHCAHTOA
[Right Triangles Only] sinθ = opposite over hypotenuse

Step-by-step explanation:

Step 1: Identify

Angle θ = ∠R

Opposite Leg of ∠R = 10√3

Hypotenuse = 20

Step 2: Solve

Substitute in variables [sine]: $\displaystyle sin(R^\circ) = \frac{10\sqrt{3}}{20}$
[Equality Property] Trig inverse: $\displaystyle R^\circ = sin^{-1}(\frac{10\sqrt{3}}{20})$
Evaluate trig: $\displaystyle R = 60^\circ$