Answer:
A non-equilateral rhombus.
Step-by-step explanation:
We can solve this graphically.
We start with square:
ABCD
with:
A = (11, - 7)
B = (9, - 4)
C = (11, - 1)
D = (13, - 4)
Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:
AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13
BC = √( (11 - 9)^2 + (-1 -(-4))^2) = √13
CD = √( (11 - 13)^2 + (-1 -(-4))^2) = √13
DA = √( (11 - 13)^2 + (-7 -(-4))^2) = √13
And we change C by C' = (11, 1)
In the image you can see the 5 points and the figure that they make:
The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.
Answer:8. h(t) = -6 ((t-6) -3.7)^2 + 82.14 +20
9.b) At about 7.4 seconds.
Step-by-step explanation
Yes, on #7 the function is located 3 places to the right and 2.5 up, but that's just counting the tiny squares. If you look at the number and problem, on #8, you can't add +2.5, because the rocket wasn't on a platform 2.5 feet high. Remember that outside the parentheses + means up and - means down. So add + 20(ft). but for question 8, and 9. b), try these answers. please mark brainlest
Y=2(-1)^2-6(-1)+3
y=2+6+3
y=8+3
y=11
Say x = 12 and y = 4
12 - 4 = 8
Number 1
2(12) - 4(4) = 8
24 - 16 = 8
Number 1 is your Answer
Look at the sample space below. {1, 2, 3, 7, 9, 10, 15, 19, 20, 21} When chosen randomly, what is the probability of picking an
maw [93]
Answer:
the probability of picking an odd number is 7/10
