The length of the segment ac is 10.3 cm
<h3>How to determine the length ac?</h3>
The segments are given s:
ab = 7.8cm
bc = 25mm
Point b is located between points a and c.
So, we have:
ac = ab + bc
Substitute known values
ac = 7.8cm + 25mm
Express mm a cm
ac = 7.8cm + 2.5cm
Evaluate the sum
ac = 10.3 cm
If the point b lies on segment ac, then there can be only one solution
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So, to find the constant we do this:
1.2n = 93,000,000
so n = 77500000So, with this constant, we multiply n with 0.86
0.86n = <span>66650000
So Venus is about </span><span>66,650,000 million miles away from the sun</span>
The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
7. p=0.4
i dont know about 3
or 6