H(t) = Ho +Vot - gt^2/2
Vo = 19.6 m/s
Ho = 58.8 m
g = 9.8 m/s^2
H(t) = 58.8 + 19.6t -9.8t^2/2 = 58.8 + 19.6t - 4.9t^2
Maximun height is at the vertex of the parabole
To find the vertex, first find the roots.
58.8 + 19.6t - 4.9t^2 = 0
Divide by 4.9
12 + 4t - t^2 = 0
Change sign and reorder
t^2 - 4t -12 = 0
Factor
(t - 6)(t + 2) =0 ==> t = 6 and t = -2.
The vertex is in the mid point between both roots
Find H(t) for: t = [6 - 2]/2 =4/2 = 2
Find H(t) for t = 2
H(6) = 58.8 + 19.6(2) - 4.9(2)^2 = 78.4
Answer: the maximum height is 78.4 m
Answer:
B. (x-3)^2
Step-by-step explanation:
x^2-6x+9 = (x-3)^2
(a-b)^2=a^2-2ab+b^2
(a+b)^2=a^2+2ab+b ^2
(Use order of operations(PEMDAS))
14(4)+28-12(5)
56+28-60
84-60
24
solution=24
I believe the person meant use pemdas! (order of opporations.)
you know what that is, right ? if you have questions feel free to message me!
1/3 is a simplified fraction
