1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
s344n2d4d5 [400]
3 years ago
14

What two square roots are used to estimate the square root of 67

Mathematics
2 answers:
Georgia [21]3 years ago
7 0
It would be 8.185 since there aren't 2 numbers that evenly go into 67
juin [17]3 years ago
5 0

The root of 64 and 81

You might be interested in
How did you solve the equation
Vsevolod [243]
What equation ?? 0-0
3 0
2 years ago
What is the value of 6n - 2 when n = 3?
Yuliya22 [10]

Answer:

16

Step-by-step explanation:

Substitute 3 for n,

6(3) - 2

then multiply

18 - 2

then subtract

16

8 0
3 years ago
For the function defined by f(t)=2-t, 0≤t<1, sketch 3 periods and find:
Oksi-84 [34.3K]
The half-range sine series is the expansion for f(t) with the assumption that f(t) is considered to be an odd function over its full range, -1. So for (a), you're essentially finding the full range expansion of the function

f(t)=\begin{cases}2-t&\text{for }0\le t

with period 2 so that f(t)=f(t+2n) for |t| and integers n.

Now, since f(t) is odd, there is no cosine series (you find the cosine series coefficients would vanish), leaving you with

f(t)=\displaystyle\sum_{n\ge1}b_n\sin\frac{n\pi t}L

where

b_n=\displaystyle\frac2L\int_0^Lf(t)\sin\frac{n\pi t}L\,\mathrm dt

In this case, L=1, so

b_n=\displaystyle2\int_0^1(2-t)\sin n\pi t\,\mathrm dt
b_n=\dfrac4{n\pi}-\dfrac{2\cos n\pi}{n\pi}-\dfrac{2\sin n\pi}{n^2\pi^2}
b_n=\dfrac{4-2(-1)^n}{n\pi}

The half-range sine series expansion for f(t) is then

f(t)\sim\displaystyle\sum_{n\ge1}\frac{4-2(-1)^n}{n\pi}\sin n\pi t

which can be further simplified by considering the even/odd cases of n, but there's no need for that here.

The half-range cosine series is computed similarly, this time assuming f(t) is even/symmetric across its full range. In other words, you are finding the full range series expansion for

f(t)=\begin{cases}2-t&\text{for }0\le t

Now the sine series expansion vanishes, leaving you with

f(t)\sim\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi t}L

where

a_n=\displaystyle\frac2L\int_0^Lf(t)\cos\frac{n\pi t}L\,\mathrm dt

for n\ge0. Again, L=1. You should find that

a_0=\displaystyle2\int_0^1(2-t)\,\mathrm dt=3

a_n=\displaystyle2\int_0^1(2-t)\cos n\pi t\,\mathrm dt
a_n=\dfrac2{n^2\pi^2}-\dfrac{2\cos n\pi}{n^2\pi^2}+\dfrac{2\sin n\pi}{n\pi}
a_n=\dfrac{2-2(-1)^n}{n^2\pi^2}

Here, splitting into even/odd cases actually reduces this further. Notice that when n is even, the expression above simplifies to

a_{n=2k}=\dfrac{2-2(-1)^{2k}}{(2k)^2\pi^2}=0

while for odd n, you have

a_{n=2k-1}=\dfrac{2-2(-1)^{2k-1}}{(2k-1)^2\pi^2}=\dfrac4{(2k-1)^2\pi^2}

So the half-range cosine series expansion would be

f(t)\sim\dfrac32+\displaystyle\sum_{n\ge1}a_n\cos n\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}a_{2k-1}\cos(2k-1)\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}\frac4{(2k-1)^2\pi^2}\cos(2k-1)\pi t

Attached are plots of the first few terms of each series overlaid onto plots of f(t). In the half-range sine series (right), I use n=10 terms, and in the half-range cosine series (left), I use k=2 or n=2(2)-1=3 terms. (It's a bit more difficult to distinguish f(t) from the latter because the cosine series converges so much faster.)

5 0
3 years ago
PLEASE HELP
Oksana_A [137]

Answer:

A racer has just completed his first lap at a speed of 198m/s. Now his speed decrease or he decelerateted at 195m/s after 2s of his completion of first lap, as soon as he saw a curve path(line segment R). He then moved at a constant speed of 195m/s for the next 2s(line segment s). Then the race track after 4s of the completion of first lap was straight, so the racer accelerated to 200m/s within 2s( line segment T) and traveled at a constant speed for the next 6s( line segment U). After 12s from the first lap completion, he immediately saw a curve track, so he decelerateted to the speed of 194m/s within 3s( line segment V).

Hope it helped.

please mark brainliest

4 0
2 years ago
Solve and make a table ( you may decide what the topic is and the value is.Algebra I)
ratelena [41]

Answer:

Hello...

I'm new user here.

Can you teach me how to use brainly? Please, it would bey favour.

I have just downloaded the app and don't know how to use.

6 0
2 years ago
Read 2 more answers
Other questions:
  • Someone please help:)
    13·1 answer
  • Find the equation of the linear function represented by the table below in
    8·1 answer
  • A phone manufacturer wants to compete in the touch screen phone market. Management understands that the leading product has a le
    11·1 answer
  • Kyle's car average 380 miles on a 16-gallon tank of gas. How far can he drive on 6 gallons of gas?
    11·1 answer
  • I don’t understand how to set up the equation and expressions, I pretty much need help with everything
    13·2 answers
  • Solve: 3,125 = 5-10 + 3x<br> DONE
    13·1 answer
  • The manager of a grocery store has selected a random sample of 100 customers. The average length of time it took these 100 custo
    5·1 answer
  • You use 4 boxes of rice to serve 13 people. If you want to serve 39 people, what should you do?
    10·2 answers
  • PLEASE ANSWER QUICKLY WILL GIVE BRAINLIEST IF CORRECT
    5·2 answers
  • Find the value of y in the drawing below <br> 3y+13 and 2y+25
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!