Answer:
Explanation:
Magnetic field due to a long wire
= 10⁻⁷ x 2i / r where i is current in the wire and r is distance of the point from the wire
In the given case magnetic field
B = 10⁻⁷ x 2i / r
= 10⁻⁷ x 2x 1.3 / .8 x 10⁻²
= 3.25 x 10⁻⁵ T
= 32.5 x 10⁻⁶ T
It will create a deflecting torque on the compass needle
Let after turning by angle θ , equilibrium point is reached
at this point , deflecting torque = restoring torque by earth's magnetic field
MB cosθ = MHsinθ , M is magnetic moment of magnetic needle , H is horizontal component of earth's magnetic field.
Tanθ = B / H
= 32.5 / 29
=1.20
θ = 50 degree approx .
Answer:
x = 0.6034 m
Explanation:
Given
L = 5 m
Wplank = 225 N
Wman = 522 N
d = 1.1 m
x = ?
We have to take sum of torques about the right support point. If the board is just about to tip, the normal force from the left support will be going to zero. So the only torques come from the weight of the plank and the weight of the man.
∑τ = 0 ⇒ τ₁ + τ₂ = 0
Torque come from the weight of the plank = τ₁
Torque come from the weight of the man = τ₂
⇒ τ₁ = + (5 - 1.1)*(225/5)*((5 - 1.1)/2) - (1.1)*(225/5)*((1.1)/2) = 315 N-m (counterclockwise)
⇒ τ₂ = Wman*x = 522 N*x (clockwise)
then
τ₁ + τ₂ = (315 N-m) + (- 522 N*x) = 0
⇒ x = 0.6034 m
Explanation:
First, we need to calculate the constant force, that is, the ratio between the applied force and the rubber stretch due to the application of the force:
Now, we can know how far will an 18N force stretch the rubber. From (1):
The work done by the external force on the rubber is equal to its elastic potential energy: