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Thepotemich [5.8K]

4 years ago

11

An object is propelled along a straight-line path by a force. If the net force were doubled, the object's acceleration would be_

______.

1 answer:

nikdorinn [45]4 years ago

8 0

Answer:

double

Explanation:

According to the newton's second law

force = mass x acceleration

So, acceleration is directly proportional to the force.

As the force is doubles, the acceleration is also doubled.

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ira [324]

Answer:

i would say the third one

Explanation:

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5 0

3 years ago

A potential energy function is given by U(x)=(3.00J)x+(1.00J/m^2)x^3. What is the force function F(x) (in newtons) that is assoc

snow_lady [41]

Answer:

$F(x)=-3 N -(3N/m^2) x^2$

Explanation:

The force is equal to the negative of the derivative of the potential energy function:

$F=-\frac{dU}{dx}$

In this problem, the potential energy function is

$U(x)=3 x + 1 x^3$

Therefore, the force function is:

$F(x)=-\frac{dU}{dx}=-\frac{d}{dx}(3x+1x^3)=-3-3x^2$

So, adding the units of measurement,

$F(x)=-3 N -(3N/m^2) x^2$

4 0

4 years ago

PLZ HELP ASAP! TYSM! I WILL AWARD BRAINLIEST!

Taya2010 [7]

Answer:

im not smart enough, all i figured out is the track is going 1.2 miles every minute

Explanation:

7 0

3 years ago

A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec

Ugo [173]

Answer:

a circular path

Explanation:

In a magnetism field if a charged particle having a charge of magnitude '' enters such that its velocity vector V is 90° to the direction of the magnetic field "B'', then it will experience a force, called Lorentz force F

$F = V\times B$

According to the property of cross-product, the Lorentz force (F) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path.

3 0

3 years ago

Two large rectangular aluminum plates of area 180 cm2 face each other with a separation of 3 mm between them. The plates are cha

lbvjy [14]

Answer:

Electric flux;

Φ = 30.095 × 10⁴ N.m²/C

Explanation:

We are given;

Charge on plate; q = 17 µC = 17 × 10^(-6) C

Area of the plates; A_p = 180 cm² = 180 × 10^(-4) m²

Angle between the normal of the area and electric field; θ = 4°

Radius;r = 3 cm = 3 × 10^(-2) m = 0.03 m

Permittivity of free space;ε_o = 8.85 × 10^(-12) C²/N.m²

The charge density on the plate is given by the formula;

σ = q/A_p

Thus;

σ = (17 × 10^(-6))/(180 × 10^(-4))

σ = 0.944 × 10^(-3) C/m²

Also, the electric field is given by the formula;

E = σ/ε_o

E = (0.944 × 10^(-3))/(8.85 × 10^(-12))

E = 1.067 × 10^(8) N/C

Now, the formula for electric flux for uniform electric field is given as;

Φ = EAcos θ

Where A = πr² = π × 0.03² = 9π × 10^(-4) m²

Thus;

Φ = 1.067 × 10^(8) × 9π × 10^(-4) × cos 4

Φ = 30.095 × 10⁴ N.m²/C

3 0

3 years ago