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Anestetic [448]
2 years ago
8

A line passes through the points (2, 0) and (3, 3). What is its equation in slope-intercept

Mathematics
1 answer:
pickupchik [31]2 years ago
8 0

Step-by-step explanation:

Write an equation, of the slope intercept form. of the line passing through the points (2,3) and (4.6)

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What is the are of the walls and cellings ? & what is the area of the window? How many cans o paint should she buy ?
nignag [31]

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3 0
3 years ago
Need help thanks <br><br><br> ---
Molodets [167]

the answer is A

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6 0
3 years ago
Must include an explanation !!<br><br> solve for x
Ira Lisetskai [31]

Answer:

x=5

Step-by-step explanation:

Volume of a rectangular prism=\frac{1}{2}b x l x h

Set up you equation

120=\frac{1}{2}(4 x 12 x x)

Multiply inside the parentheses

120=\frac{1}{2}(48x)

Multiply by \frac{1}{2}

120=24x

Divide by 24 on both sides

5=x

Check you answer

Volume of a rectangular prism=\frac{1}{2}b x l x h

Set up your equation

\frac{1}{2}(12 x 5 x 4)

Multiply inside the parentheses

\frac{1}{2}(240)

Multiply by \frac{1}{2}

V=120yd³

8 0
3 years ago
Please help find the probability that x &gt;25.
bija089 [108]

Answer

The total probability is one:

Total probability of being greater than 25 is 1 because the totals of all values less than 25 is 1.

5 0
3 years ago
A punch glass is in the shape of a hemisphere with a radius of 5 cm. If the punch is being poured into the glass so that the cha
Galina-37 [17]

Answer:

28.27 cm/s

Step-by-step explanation:

Though Process:

  • The punch glass (call it bowl to have a shape in mind) is in the shape of a hemisphere
  • the radius r=5cm
  • Punch is being poured into the bowl
  • The height at which the punch is increasing in the bowl is \frac{dh}{dt} = 1.5
  • the exposed area is a circle, (since the bowl is a hemisphere)
  • the radius of this circle can be written as 'a'
  • what is being asked is the rate of change of the exposed area when the height h = 2 cm
  • the rate of change of exposed area can be written as \frac{dA}{dt}.
  • since the exposed area is changing with respect to the height of punch. We can use the chain rule: \frac{dA}{dt} = \frac{dA}{dh} . \frac{dh}{dt}
  • and since A = \pi a^2 the chain rule above can simplified to \frac{da}{dt} = \frac{da}{dh} . \frac{dh}{dt} -- we can call this Eq(1)

Solution:

the area of the exposed circle is

A =\pi a^2

the rate of change of this area can be, (using chain rule)

\frac{dA}{dt} = 2 \pi a \frac{da}{dt} we can call this Eq(2)

what we are really concerned about is how a changes as the punch is being poured into the bowl i.e \frac{da}{dh}

So we need another formula: Using the property of hemispheres and pythagoras theorem, we can use:

r = \frac{a^2 + h^2}{2h}

and rearrage the formula so that a is the subject:

a^2 = 2rh - h^2

now we can derivate a with respect to h to get \frac{da}{dh}

2a \frac{da}{dh} = 2r - 2h

simplify

\frac{da}{dh} = \frac{r-h}{a}

we can put this in Eq(1) in place of \frac{da}{dh}

\frac{da}{dt} = \frac{r-h}{a} . \frac{dh}{dt}

and since we know \frac{dh}{dt} = 1.5

\frac{da}{dt} = \frac{(r-h)(1.5)}{a}

and now we use substitute this \frac{da}{dt}. in Eq(2)

\frac{dA}{dt} = 2 \pi a \frac{(r-h)(1.5)}{a}

simplify,

\frac{dA}{dt} = 3 \pi (r-h)

This is the rate of change of area, this is being asked in the quesiton!

Finally, we can put our known values:

r = 5cm

h = 2cm from the question

\frac{dA}{dt} = 3 \pi (5-2)

\frac{dA}{dt} = 9 \pi cm/s// or//\frac{dA}{dt} = 28.27 cm/s

5 0
3 years ago
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