gene for temperature regulation, gene for production of nails, gene for production of fur. these should be the answer because the chart shows them as having the same size and color alleles, which should make them homozygous and dominant.
Answer:
The answer is A precipitation reaction.
The correct answer is that a bacteriophage lambda chromosome containing the human collagen gene, because Recombinant DNA is the name given to DNA molecules that have part of DNA derived from two or more sources, usually these sources are different species. Recombinant DNA technology is also known as molecular cloning or even gene cloning.
B. A bacteriophage lambda chromosome containing the human collagen gene
<h3>How is recombinant DNA produced?</h3>
Obtaining recombinant DNA is based on the molecular cloning technique. The process can be summarized as follows:
- The first step is to isolate a DNA fragment, which contains the gene of interest. Remember that each gene makes a protein.
- The gene of interest, now isolated, is placed in a medium with a fragment of circular bacterial DNA, the plasmid and the restriction enzymes.
- The bacterial plasmid has the ability to insert a fragment of DNA external to its own genome.
<h3>What is DNA and what is it for?</h3>
DNA is the structure responsible for the transmission of all genetic characteristics — such as eye, skin and hair color, physiognomy, among others — in the process of reproduction of living beings. Thus, the main function of DNA is to transport information contained in its sequences, called genes.
Learn more about DNA in brainly.com/question/264225
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Answer: 1/16, or approximately 6.25% (see explanation below)
Explanation:
Answering this question requires two steps.
First, we need to figure out the probability that this couple will have a child with albinism in the first place. We know the following:
- Both parents are unaffected.
- The couple has already had one affected child.
- Albinism follows an autosomal recessive inheritance pattern.
Let ( M = normal gene ) and ( m = mutated gene ). Since the condition is recessive, the affected child can be assumed to have a “mm” genotype. Barring the possibility of a de novo mutation (which are assumed to be rare), the affected child must have inherited one ”m” allele from each parent. Since both of them are unaffected, however, we can assume that they are both carriers (genotype “Mm”). In conclusion, 1/4 of their offspring (25%) <em>for any given pregnancy</em> may be expected to have albinism. See the resulting Punnett square:
<u> | M | m </u>
<u>M | MM | Mm </u>
<u>m | Mm | mm </u>
Note that the question asks about the probability that not one but two consecutive births result in affected children. Since it can be assumed that both events are independent (meaning: the outcome of a pregnancy does not influence the outcome of following ones), we may apply the rule of multiplication for probabilities. The final answer is therefore 1/4 * 1/4 = 1/16.
