Answer:
Teagan is dividing 6 by 11. If she continues the process, what will keep repeating in the quotient?
The sequence 05
Only the digit 5
The sequence 54
Only the digit 4
The sequence 54 is the final answer.
Step-by-step explanation:
Given:
A a fraction 6/11 which Teagan is dividing we have to find the repeating quotient.
Here the divisor is 11 and the dividend is 6.
Lets say that the quotient is "q" .
And we know that:
⇒ Dividend / divisor = quotient
Or
In mixed fraction.
⇒ Dividend / divisor = quotient + (remainder/ divisor)
Finding the values of "q".
⇒
⇒
Explanation:
- To divide with we have to take a decimal in quotient which allows us to have a zero in each step in the quotient.
- After putting zero the dividend will become and then we can apply ... in the quotient and in the numerator.
- In third step we will subtract with that will give us putting a zero with it it will be now ,and the closet multiple of is , with the quotient and and will continue to be divided.
- The fraction is a rational numbers as the decimals occurring are repeating decimals in the quotient.
Our final answer from the option is : C
The sequence 54 will be repeating.
Answer:
The width of the rectangle is 4x^24x
2
4, x, squared
The length of the rectangle is 2x^3+3x+52x
3
+3x+5
Step-by-step explanation:
Use pemdas, parenthesis, exponents, multiplication/division, addition/subtraction. thats the best way to explain how to do this.
Answer:12 buckets
Step-by-step explanation:
Try this option:
the functions y=sin(x) and y=cos(x) are the standart functions; it means, the period of each is 2π, maximum value is '1', minimum value is '-1'.
Using the properties described above, to find the max. value for the function y=2cos(x): 2*1=2, where 2- the amplitude of the given function, 1- maximum of the standart function;
the max. value for the function y=3sin(x+π): 3*1=3, where 3 - the amplitude of the given function, 1- maximum of the standart function.
For more details see the attached picture.
In other words, common equation for such functions is y=A*sin(ωx+Ф), where A- amplitude, ω - frequency and Ф - initial phase of the given function.
Max. and min. values depend on A, all the points of the function repeat every 2π, including max. and min. values.