Number one is A ) 4 units to the left
PEMDAS parentheses exponents multiply divide add subtract
Answer:
Part 1) 
Part 2) 
Part 3) 
Step-by-step explanation:
<u><em>The complete question is</em></u>
Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B
The picture of the question in the attached figure
Part 1) Write the ratio equivalent to: Sin B
we know that
In the right triangle ABC
----> by SOH (opposite side divided by the hypotenuse)
substitute the values
Part 2) Write the ratio equivalent to: Csc A
we know that
In the right triangle ABC
-----> by SOH (opposite side divided by the hypotenuse)
substitute the values
therefore
Part 3) Write the ratio equivalent to: Cot A
we know that
In the right triangle ABC
-----> by TOA (opposite side divided by the adjacent side)
substitute the values
therefore
You take 5b and -2b which will make: 3b
then combine -11 and 6 to get: -5
full answer: 3b-5
Answer:
Below in bold.
Step-by-step explanation:
The identity is of the form
(a + b)^2 = a^2 + 2ab + b^2.
a) Sqrt 49 = 7 and we need + 28 as the middle coefficient . We get this with
2*7 + 2*7 so the first coefficient is 2*2 = 4.
So * = 4a^2.
(2a + 7)^2 = (2a + 7)(2a + 7) = 4x^2 + 14a + 14a + 49.
b) -6 * -6 = 36 -24 = 2*-6 + 2 *-6 so the last term is 4x^2
c) The middle term must be an 'ab' term.
sqrt 6.25 = 2.5 and sqrt 1/4 = 1/2
So the coefficient of the middle term is 2.5 * 1/2 + 2.5 * 1/2
= 2.5
So the middle term is 2.5ab.
d) The first term will be in b^2.
100 = 10* 10 and we need 2 as a middle term so coefficient of the first term
will be 1/100 or 0.01. as the 2 comes from 0.1 * 10 + 0.01 * 10 and (0.1)^2 = 0.01
So it is 0.01b^2.
