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Tcecarenko [31]
3 years ago
8

Does anyone know how to solve this ?

Mathematics
1 answer:
crimeas [40]3 years ago
3 0

9514 1404 393

Answer:

  see below

Step-by-step explanation:

Make use of the quadratic formula.

For equation ax² +bx +c = 0, the solutions are ...

  x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

Here, you have a=1, b=-1, c=1, so the solutions are ...

  x=\dfrac{-(-1)\pm\sqrt{(-1)^2-4(1)(1)}}{2(1)}=\dfrac{1\pm\sqrt{1-4}}{2}=\dfrac{1\pm i\sqrt{3}}{2}\\\\\boxed{x=\dfrac{1+i\sqrt{3}}{2}\text{ and }x=\dfrac{1-i\sqrt{3}}{2}}

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Answer:

The coordinates of the image of point A (2, -7) are A'(-1,-2).

Step-by-step explanation:

Note: The sign is missing between y and 5 in the rule of transitional.

Consider the rule of translation is

(x,y)\Rightarrow (x-3,y+5)

We need to find the image of point A (2, -7).

Substitute x=2 and y=-7 in the above rule.

A(2,-7)\Rightarrow A'(2-3,-7+5)

A(2,-7)\Rightarrow A'(-1,-2)

Therefore, the coordinates of the image of point A (2, -7) are A'(-1,-2).

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2 years ago
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Answer:

Step-by-step explanation:

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Step-by-step explanation:


7 0
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Pls help this packet is driving me crazy!!
AleksAgata [21]
Proportion A
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 y = 9x
 The slope is:
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