Answer:
the action of building something, typically a large structure.
Explanation:
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Answer: d) Inductors
Explanation: Inductors are the electric component commonly known by the name of coils as well. The work done by inductors is when the electric current flows through the coils of the wire then there is production of the magnetic field. They are the component that have the inductance in particular amount according to the circuit.So, coils of various dimensions are designed to introduce specified amount of inductance into a circuit are called inductors.
Given :
Capacitor , C = 55 μF .
Energy is given by :
.
To Find :
The current through the capacitor.
Solution :
Energy in capacitor is given by :

Now , current i is given by :
![i=C\dfrac{dv}{dt}\\\\i=C\dfrac{d[603.02cos(337t)]}{dt}\\\\i=-55\times 10^{-6}\times 603.03\times 337\times sin(337t)\\\\i=-11.18\ sin(337t)](https://tex.z-dn.net/?f=i%3DC%5Cdfrac%7Bdv%7D%7Bdt%7D%5C%5C%5C%5Ci%3DC%5Cdfrac%7Bd%5B603.02cos%28337t%29%5D%7D%7Bdt%7D%5C%5C%5C%5Ci%3D-55%5Ctimes%2010%5E%7B-6%7D%5Ctimes%20603.03%5Ctimes%20337%5Ctimes%20sin%28337t%29%5C%5C%5C%5Ci%3D-11.18%5C%20sin%28337t%29)
( differentiation of cos x is - sin x )
Therefore , the current through the capacitor is -11.18 sin ( 377t).
Hence , this is the required solution .
Answer: Volume= 1.16 yd³
Explanation:
We are given the in-situ moisture content= 18% and moist unit weight= 105 pcf
First we find out the dry unit weight
Dry unit weight= Moist unit weight / (1+ moisture content)
Dry unit weight= 
Dry unit weight= 88.983 pcf
Now, to find the volume ( in terms of each cubic yard i.e 1 yd³ we have
Volume = Dry unit weight compacted / Dry unit weight (in-situ) * 1 yd³
Volume= 
Volume= 1.16 yd³