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ad-work [718]
3 years ago
9

To purchase a new car, you borrow $20,000. The bank offers a 6-year loan at an interest rate of 3.25% compounded annually. If yo

u make only one payment at the end of the loan period, repaying the principal and interest: Which time value factor should be used to solve this problem?
Engineering
1 answer:
Natalka [10]3 years ago
6 0

Answer:

SPCA factor

Single payment compound amount factor.

Total amount pay A = $24,230.95 (Approx)

Interest paid = $4,230.95  (Approx)

Explanation:

Given:

P = $20,000

n = 6 year

r = 3.25%

Find:

Total amount pay A

Computation:

A=p(1+r)ⁿ

A=20,000[1+3.5%]⁶

A=20,000[(1.0325)⁶]

Total amount pay A = $24,230.95 (Approx)

Interest paid = $24,230.95 - 20,000

Interest paid = $4,230.95  (Approx)

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Meaning of construction
sammy [17]

Answer:

the action of building something, typically a large structure.

Explanation:

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8 0
3 years ago
Coils of various dimensions designed to introduce specified amounts of inductance into a circuit are called (a) semiconductors (
Delicious77 [7]

Answer: d) Inductors

Explanation:  Inductors are the electric component commonly known by the name of coils as well. The work done by inductors is when the electric current flows through the coils of the wire then there is production of the magnetic field. They are the component that have the inductance in particular amount according to the circuit.So, coils of various dimensions are designed to introduce specified amount of inductance  into a circuit are called inductors.

4 0
3 years ago
How is everyone doing on this fine January da 12th?
Kay [80]
Great thanks for asking!
4 0
3 years ago
Read 2 more answers
A 55-μF capacitor has energy ω (t) = 10 cos2 377t J and consider a positive v(t). Determine the current through the capacitor.
mart [117]

Given :

Capacitor , C = 55 μF .

Energy is given by :

\omega(t)=10cos^2 (377t)\ J .

To Find :

The current through the capacitor.

Solution :

Energy in capacitor is given by :

\omega=\dfrac{Cv^2}{2}\\\\v=\sqrt{\dfrac{2\omega}{C}}\\\\v=\sqrt{\dfrac{2\times 10cos^2 (377t)}{55\times 10^{-6}}}\\\\v=cos(337t)\sqrt{\dfrac{2\times 10}{55\times 10^{-6}}}\\\\v=603.02\ cos( 337t)

Now , current i is given by :

i=C\dfrac{dv}{dt}\\\\i=C\dfrac{d[603.02cos(337t)]}{dt}\\\\i=-55\times 10^{-6}\times 603.03\times 337\times sin(337t)\\\\i=-11.18\ sin(337t)

( differentiation of cos x is - sin x )

Therefore , the current through the capacitor is -11.18 sin ( 377t).

Hence , this is the required solution .

6 0
3 years ago
The in situ moisture content of a soil is 18% and the moist (total) unit weight is 105 pcf. The soil is to be excavated and tran
densk [106]

Answer: Volume= 1.16 yd³

Explanation:

We are given the in-situ moisture content= 18% and moist unit weight= 105 pcf

First we find out the dry unit weight

Dry unit weight= Moist unit weight / (1+ moisture content)

Dry unit weight= \frac{105}{1.18}

Dry unit weight= 88.983 pcf

Now, to find the volume ( in terms of each cubic yard i.e 1 yd³ we have

Volume = Dry unit weight compacted / Dry unit weight (in-situ) * 1 yd³

Volume= \frac{103.5}{88.983} * 1

Volume= 1.16 yd³

6 0
4 years ago
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