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Lina20 [59]
3 years ago
8

Let logp/n=5 and logm/n=9

Mathematics
1 answer:
lorasvet [3.4K]3 years ago
8 0

Answer:

we know that

log (P/N) = log P - log N

so

log P - log N = 5----------------> equation 1

log (M/N) = log M - log N  

so

log M - log N = 9 ------------------> equation 2  

If you subtract equation 2 from equation 1,

you have

log M - log P = 4  

That means that log (M/P) = 4 ----> 10^4 = M/P ---> M = 10000P

the answer is

the relationship between P and M is  

M = 10000P

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What is the value of x in theequation 2.5 (6x - 4) = 10 + 4 (1.5 +0.5 x)?
Zarrin [17]

Answer:

x = 2

Step-by-step explanation:

Let's solve your equation step-by-step.

2.5(6x−4)=10+4(1.5+0.5x)

Step 1: Simplify both sides of the equation.

2.5(6x−4)=10+4(1.5+0.5x)

(2.5)(6x)+(2.5)(−4)=10+(4)(1.5)+(4)(0.5x)(Distribute)

15x+−10=10+6+2x

15x−10=(2x)+(10+6)(Combine Like Terms)

15x−10=2x+16

15x−10=2x+16

Step 2: Subtract 2x from both sides.

15x−10−2x=2x+16−2x

13x−10=16

Step 3: Add 10 to both sides.

13x−10+10=16+10

13x=26

Step 4: Divide both sides by 13.  

x=2

5 0
2 years ago
If a person tosses a coin 23 times, how many ways can he get 11 heads
EastWind [94]

Tossing a coin is a binomial experiment.

Now lets say there are 'n' repeated trials to get heads. Each of the trials can result in either a head or a tail.

All of these trials are independent since the result of one trial does not affect the result of the next trial.

Now, for 'n' repeated trials the total number of successes is given by

_{r}^{n}\textrm{C}

where 'r' denotes the number of successful results.

In our case n=23 and r=11,

Substituting the values we get,

_{11}^{23}\textrm{C}=\frac{23!}{11!\times 12!}

\frac{23!}{11!\times 12!}=1352078

Therefore, there are 1352078 ways to get heads if a person tosses a coin 23 times.


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What is an integer of 22,8,7,2,-11 from greatest to least
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Well, i don't know what you're asking, but -11,2,7,8,22?
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The correct answer would be -23
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