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Snowcat [4.5K]
3 years ago
5

Which graph represents (x,y)-pairs that make the equation y=0.5+5 true?

Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

Answer:

Choice C

Step-by-step explanation:

Notice that the equation y = 0.5 x + 5

is a linear equation so the points that are solutions of it must reside on a line. Option A does not show aligned points, so it cannot be a possible answer.

Option B: we look into the given points and notice that just the first one (1, 0) is NOT a solution to the equation because:

y = 0.5 (1) + 5 = 5.5 and not "0"

Option C: This is the correct answer, since all those points satisfy the equation

Point (2, 6)  -->  y = 0.5 (2) + 5 = 1 + 5 = 6

Point (4, 7)  -->   y = 0.5 (4) + 5 = 2 + 5 = 7

Point (6, 8) -->   y = 0.5 (6) + 5 = 3 + 5 = 8

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How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
4 years ago
Which of the following describes bias that may arise from the results?
velikii [3]
Answer: I think A
Epian:
8 0
3 years ago
If a can is 20cm Haigh X 8cm diameter what is the volume
sattari [20]
Radius=8/2=4cm

volume=4*4*3.14*20=1004.8

The answer is  1004.8cm₃

7 0
3 years ago
Simplify (x^3/x^2)^2 . Explain your steps.
Helen [10]

Answer:

Step-by-step explanation:

(x^3

x^2)^2

X³   )²

X²

X³*²

X²*²

X ⁶

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8 0
3 years ago
Z varies jointly as x and y. z=60 when x=5 and y=6. find z when x = 7 and y=3
Aneli [31]

Answer:

z = 42

Step-by-step explanation:

The question can be answered in 2 steps as follows:

Step 1: Calculation of the constant of the variation

The equation for the joint variation can be given as follows:

z = cxy ................... (1)

Where;

z = 60

c = constant = ?

x = 5

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Substituting the values into equation (1) and solve c, we have:

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Step 2: find z when x = 7 and y = 3

Since from Step 1 c = 2, we now use equation (1) and substitute the values into it to find z as follows:

z = 2 * 7 * 3

z = 42

4 0
3 years ago
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