-2x - 3x = -5x
8 - 4 = 4
-5x + 4
Answer:
There is no solution to that equation.
Step-by-step explanation:
First thing to do is to put the second equation in terms of y. To do so the equation becomes y= 2/3x+5. Comparing those two equation you can see that the slopes are the same and thus means that the system has no solution.
Another way to see this is by graphing both of thee equations is a calculator and seeing there are no points of intersection.
Answer:
Length = 3 cm
Width = 1 cm
Step-by-step explanation:
Let the length of rectangle be l and width of rectangle be w.
According to problem,
l = 3w {Length of rectangle is equal to triple the width}
And Perimeter,P = 8 cm
Since, P = 2 ( l + w )
or 8 = 2( l + w)
Plug l =3w in the above perimeter equation.
We get:
8 = 2( 3w + w)
8 = 2(4w)
8 = 8w
or w = 1 cm
Then length ,l = 3w =3 * 1 = 3 cm
Hence length of rectangle is 3cm and width of rectangle is 1cm.
Answer:
The relative frequency is found by dividing the class frequencies by the total number of observations
Step-by-step explanation:
Relative frequency measures how often a value appears relative to the sum of the total values.
An example of how relative frequency is calculated
Here are the scores and frequency of students in a maths test
Scores (classes) Frequency Relative frequency
0 - 20 10 10 / 50 = 0.2
21 - 40 15 15 / 50 = 0.3
41 - 60 10 10 / 50 = 0.2
61 - 80 5 5 / 50 = 0.1
81 - 100 <u> 10</u> 10 / 50 = <u>0.2</u>
50 1
From the above example, it can be seen that :
- two or more classes can have the same relative frequency
- The relative frequency is found by dividing the class frequencies by the total number of observations.
- The sum of the relative frequencies must be equal to one
- The sum of the frequencies and not the relative frequencies is equal to the number of observations.
Answer:
2
Step-by-step explanation:
4×2 (1/4)
The 4 would cancel out to give
2 (1/1) =2