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lord [1]
3 years ago
7

The mode of 100 120 120 140 140 100

Mathematics
2 answers:
Monica [59]3 years ago
7 0

Answer:

100, 120, 140

Step-by-step explanation:

The mode is the value that occurs most often in the sequence. All the numbers occur twice

ratelena [41]3 years ago
6 0

Answer:

100, 120, 140

Step-by-step explanation:

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Pre image ABCD was dilated to produce image A’B’C’D why is the scale factor from the pre image? Enter your answer in the box as
shepuryov [24]

The scale factor of the dilation from ABCD to A′B′C′D′ is 3.

Step-by-step explanation:

Step 1:

In the pre-image ABCD, the length of one of the sides is given as 14 units.

For the other shape A′B′C′D′, the same side as the previous shape is given as 8 units.

Step 2:

To determine the scale factor, we divide the measurement after scaling by the same measurement before scaling.

In this case, it is the given length of the sides CD and C′D′.

So the scale factor = \frac{C^{1} D^{1} }{CD} = \frac{8}{14} = \frac{4}{7} .

So the shape ABCD is dilated by a scale factor of \frac{4}{7} to produce the shape A′B′C′D′.

7 0
4 years ago
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vladimir1956 [14]

Answer for 1. X=12.5

6 0
4 years ago
Claire is figuring out the mass of some materials in her science experiment. Sample A has a mass of 8.993 grams and Sample B has
Mademuasel [1]
8.993 / .23 = 39
the answer is 39.
Hope I helped.
5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=y%2B%20%20%5Cfrac%7B13%7D%7B4%7D%20%20%3D%20%28x%5E2-%20%5Cfrac%7B1%7D%7B2%7D%20%29%5E2" id="T
zhenek [66]

Answer:    \bold{y=\dfrac{1\pm \sqrt{4x+13}}{2}}

<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's and solve for y:

y+\dfrac{13}{4}=\bigg(x-\dfrac{1}{2}\bigg)^2\\\\\\x+\dfrac{13}{4}=\bigg(y-\dfrac{1}{2}\bigg)^2\rightarrow \text{(swapped the x's and y's)}\\\\\\\sqrt{x+\dfrac{13}{4}}=\sqrt{\bigg(y-\dfrac{1}{2}\bigg)^2}\rightarrow \text{(took square root of both sides)}\\\\\\\sqrt{\dfrac{4x+13}{4}}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(created common denominator in radical)}\\\\\\ \dfrac{\sqrt{4x+13}}{2}=\pm \bigg(y-\dfrac{1}{2}\bigg)}\rightarrow \text{(simplified radical)}

\pm \dfrac{\sqrt{4x+13}}{2}=y-\dfrac{1}{2}}\rightarrow \text{(divided both sides by}\ \pm )\\\\\\\dfrac{1}{2}\pm \dfrac{\sqrt{4x+13}}{2}=y\quad \rightarrow \text{(added}\ \dfrac{1}{2}\ \text{to both sides)}\\\\\\\dfrac{1\pm \sqrt{4x+13}}{2}=y\quad \rightarrow \text{(combined numerators)}

4 0
3 years ago
7(x-2)-3(3+x)&lt;1<br><br> Solve the inequality
Zarrin [17]

7(x - 2) - 3(3 + X) greater than 1

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4 x -23 greater than 1

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x is greater than 6

4 0
3 years ago
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