2 I think it is not sure hope it helps you out
In the study the total number of males was 739 and the total number of all employees was 1501. The men who felt stressed or tensed out during work were 244 and those that never felt stressed out were 495.
Assuming that, A= Employed adults was male and B= Employed adult felt tense or stress out at work.
Then , P(A/B) = P(A∩B)/ P(B)
P(B) is the probability of having a male.
P(B) = 739/1501
P(A∩B) is the probability of a man being stressed or tensed out at work.
and P(A∩B) = 244/ 1501
Hence, P(A/B) =(244/1501)/ (739/1501)
= 244/739
= 0.3302.
Thus, the probability that the employed work felt tense or stress at work given that the employed employee was male is 0.3302
Answer:
To make x the subject of the equation means to solve the equation for x (get x by itself on one side). We do the order of operations in reverse, because we are using inverse operations. First, add the 2 to both sides (to keep the equation “balanced” we must do the same thing to both sides). y+2=3x. Then divide both sides of the equation by 3 (or multiply both sides by 1/3.
Step-by-step explanation:
Answer:
<em>Exact Form:
</em>
<em>Decimal Form:
</em>
1.875
<em>Mixed Number Form:
</em>
Since a target is a circle and the bulls-eye is also a circle, the percent of the circle that is bulls-eye would be (Area of the bulls eye)/(Area of the target)
[tex] A = \pi r^{2} \\
d = 2r \\ r = \frac{d}{2} \\\\
\frac{ \pi ( \frac{d}{2})^{2}}{ \pi ( \frac{d}{2})^{2} }= \frac{ \pi ( \frac{3}{2})^{2}}{ \pi ( \frac{15}{2})^{2} }\\
\frac{ \pi ( \frac{3}{2})^{2} }{ \pi ( \frac{15}{2})^{2} } = \frac{ \pi (1.5)^{2} }{ \pi (7.5)^{2} } \\
\frac{ \pi (1.5)}{ \pi (7.5) } = \frac{ \pi (2.25)}{ \pi (56.25)}\\
\frac{ \pi (2.25)}{ \pi (56.25)}=\frac{2.25}{56.25}= 0.04 [tex]
So the bulls-eye takes up 4% of the target.
