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podryga [215]
2 years ago
12

Kendra gets a paycheck of $300 after 5 days of work. At this rate, how much does she get paid for working 24 days?

Mathematics
2 answers:
Talja [164]2 years ago
8 0

Answer:

1440

Step-by-step explanation:

300÷5=60

60×24=1440

AleksAgata [21]2 years ago
7 0

Answer:

1440

Step-by-step explanation:

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Ra'Shaela is going to the store to buy candy. She has $3.45 in dimes and
Allushta [10]
.25 • 13 = $3.25 (13 is the # of quarters)
$3.25+ 2(.10) = .20 (2 dimes)
$3.25+.20= $3.45

3 0
3 years ago
Suppose that v is an eigenvector of matrix A with eigenvalue λA, and it is also an eigenvector of matrix B with eigenvalue λB. (
galben [10]

Answer:

(a) Yes, λ_{A}+λ_{B}

(b) Yes, λ_{A}λ_{B}

Step-by-step explanation:

First, lets understand what are eigenvectors and eigenvalues?

Note: I am using the notation λ_{A} to denote Lambda(A) sign.

v is an eigenvector of matrix A with eigenvalue λ_{A}

v is also eigenvector of matrix B with eigenvalue λ_{B}

So we can write this in equation form as

Av=λ_{A}v

So what does this equation say?

When you multiply any vector by A they do change their direction. any vector  that is in the same direction as of Av, then this v  is called the eigenvector of A. Av is λ_{A} times the original v. The number λ_{A} is the eigenvalue of A.

λ_{A} this number is very important and tells us what is happening when we multiply Av. Is it shrinking or expanding or reversed or something else?

It tells us everything we need to know!

Bonus:

By the way you can find out the eigenvalue of Av by using the following equation:

det(A-λI)=0

where I is identity matrix of the size of same as A.

Now lets come to the solution!

(a) Show that v is an eigenvector of A + B and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(A+B)(v)=Av+Bv=(λ_{A})v + (λ_{B})v=(λ_{A}+λ_{B})(v)

so,  (A+B)(v)=(λ_{A}+λ_{B})(v)

which means that v is also an eigenvector of A+B and the associated eigenvalues are λ_{A}+λ_{B}

(b) Show that v is an eigenvector of AB and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(AB)(v)=A(Bv)=A(λ_{B})=λ_{B}(Av)=λ_{B}λ_{A}(v)=λ_{A}λ_{B}(v)

so,  

(AB)(v)=λ_{A}λ_{B}(v)

which means that v is also an eigenvector of AB and the associated eigenvalues are λ_{A}λ_{B}

5 0
3 years ago
Which linear inequality is represented by the graph? y ≤ 1/2x + 2 y ≥ 1/2x + 2 y ≤ 2/3x + 2 y ≥ 2/3x + 2
patriot [66]
Post the graph and I can help
6 0
3 years ago
Read 2 more answers
in the year 2001, a person bought a new car for $22000. for each consecutive year after that, the value of the car depreciated b
igomit [66]

Answer:

To the nearest hundred dollars, the car will be worth $17,900 by 2005

Step-by-step explanation:

Firstly, we need to write the depreciation equation

We have this as:

V = I(1 - r)^t

V is the present value which is what we want to calculate

I is the initial value, the amount the cad was bought which is $22,000

r is the rate of change which is 5% = 5/100 = 0.05

t is the time difference which is 2005-2001 = 4

Substituting all these into the depreciation equation, we have it that

V = 22,000(1 -0.05)^4

V = $17,919.1375

To the nearest hundred dollars, that would be;

$17,900

7 0
3 years ago
Which expression can be used to determine the length of segment ZY?
katrin2010 [14]

As we move from point Z to point Y, x increases by 8 and y increases by 3.  Thus the length of line segment ZY is sqrt(8^2 + 3^2) = sqrt(73), by the Pythagorean Theorem.  That's approx. 8.54.

You could also leave your answer in the form √(8^2 + 3^2).

7 0
3 years ago
Read 2 more answers
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