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2 years ago

Plss help for a brainlist :)))

Mathematics

2 answers:

AnnZ [28]2 years ago

7 0

Answer:

B) 1/20

Step-by-step explanation:

For every 1 week, he gets 20$ saved up.

Hope this helps!

-kiniwih426

sveticcg [70]2 years ago

5 0

Answer:

The slope is 24

Step-by-step explanation:

Use any two points in the graph to find the slope of the graph
- - - - - - - - - - - - - - - - - - - -
Step 1. Use two points

Ex: (10, 320) & (5, 200)

Step 2. Find the slope using the two points

m = slope

m = change in y/change in x

m = (y2 - y1)/(x2 - x1)

m = (200 - 320)/(5 - 10)

m = -120/-5

m = 120/5

m = 24

The slope of the graph/line is 24

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Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

3 years ago

The track-and-field coach wants to know whether the students in the entire school prefer track races or field events. The coach

strojnjashka [21]

All students in each grade

audience: students - counts for both boys and girls.

option (B) for teachers is irrevelant.

option (C) doesn't include girls.

option (D) doesn't include the entire school

Hence, option A is correct.

8 0

2 years ago

Lve. 1. Jeremy spent $33 on 3 CDs. At this rate, how much would 5 CDs cost?

IrinaVladis [17]

It will coast $55 for 5 CDs

6 0

3 years ago

Read 2 more answers

Hey please help me with this one. - Find the value fd a

valkas [14]

Answer: a = 15

Step-by-step explanation:

6a + 10 = 3a + 55

Subtract 10 from both sides

6a = 3a + 45

Subtract 3a from both sides

3a = 45

Divide each side by 3

a = 15

5 0

3 years ago

We did not find results for: A measure of malnutrition, called the pelidisi, varies directly as the cube root of a person's w

asambeis [7]

$\bf \qquad \qquad \textit{double proportional variation}\\\\
\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
\end{array}\implies y=\cfrac{kx}{z}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\$

$\bf \begin{cases}
p=pedalisi\\
w=weight\\
s=\textit{sitting height}
\end{cases}\quad 
\begin{array}{llll}
%pelidisi, varies directly as the cube root of a person's weight in grams and inversely as the person's sitting height in centimeters.
\textit{pelidisi varies directly}\\
\textit{as cube root of weight}\\
\textit{and inversely to }\\
\textit{sitting height}
\end{array}\implies p=\cfrac{k\sqrt[3]{w}}{s}\\\\
-------------------------------$

$\bf \textit{we know that }
\begin{cases}
w=48,820\\
s=78.7\\
p=100
\end{cases}\implies 100=\cfrac{k\sqrt[3]{48820}}{78.7}
\\\\\\
100\cdot 78.7=k\sqrt[3]{48820}\implies \cfrac{7870}{\sqrt[3]{48820}}=k
\\\\\\
thus\qquad \boxed{p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{w}}{s}}
\\\\\\
\textit{now, what is \underline{p} when }
\begin{cases}
w=54,688\\
s=72.6
\end{cases}?\implies p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{54688}}{72.6}$

now, if that value is less than 100, then the fellow is "undernourished", otherwise, is overfed.

3 0

4 years ago