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natali 33 [55]
2 years ago
11

PLSSS HELLLPP MY QUARTER ENDS TMMR!!! can someone solve y=___x+___

Mathematics
1 answer:
natulia [17]2 years ago
5 0

Answer: -3/2x + 3 ⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀

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F(x)=11x -x +2 find the potential rational zeros
d1i1m1o1n [39]
X = - 1/2

In other way is x = -0.2 , x = -5^-1
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3 years ago
X + 2∕5 = 1∕3 for x.
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?

Step-by-step explanation:

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8 0
2 years ago
Solve the system by substitution.<br> [-2.5x+y = 13.5<br> 12.25x - y=-12.25
IrinaK [193]

Answer:

x = 5/39 , y = 539/39

Step-by-step explanation:

Solve the following system:

{y - 2.5 x = 13.5

12.25 x - y = -12.25

In the first equation, look to solve for y:

{y - 2.5 x = 13.5

12.25 x - y = -12.25

y - 2.5 x = y - (5 x)/2 and 13.5 = 27/2:

y - (5 x)/2 = 27/2

Add (5 x)/2 to both sides:

{y = 1/2 (5 x + 27)

12.25 x - y = -12.25

Substitute y = 1/2 (5 x + 27) into the second equation:

{y = 1/2 (5 x + 27)

1/2 (-5 x - 27) + 12.25 x = -12.25

(-5 x - 27)/2 + 12.25 x = 12.25 x + (-(5 x)/2 - 27/2) = 9.75 x - 27/2:

{y = 1/2 (5 x + 27)

9.75 x - 27/2 = -12.25

In the second equation, look to solve for x:

{y = 1/2 (5 x + 27)

9.75 x - 27/2 = -12.25

9.75 x - 27/2 = (39 x)/4 - 27/2 and -12.25 = -49/4:

(39 x)/4 - 27/2 = -49/4

Add 27/2 to both sides:

{y = 1/2 (5 x + 27)

(39 x)/4 = 5/4

Multiply both sides by 4/39:

{y = 1/2 (5 x + 27)

x = 5/39

Substitute x = 5/39 into the first equation:

{y = 539/39

x = 5/39

Collect results in alphabetical order:

Answer: {x = 5/39 , y = 539/39

5 0
3 years ago
A telephone plan charges a regular monthly amount plus charges for the number of minutes of use (x) as shown in the equation y =
In-s [12.5K]

Answer:

Slope: 0.28

y-intercept: (0,65)

4 0
2 years ago
Read 2 more answers
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