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zaharov [31]
2 years ago
9

In the diagram below, AABC-ADEC. What is the value of x?

Mathematics
1 answer:
Marina86 [1]2 years ago
7 0

Answer:

C

Step-by-step explanation:

Number 4

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Please help with this question
Iteru [2.4K]

Answer:

Inequality Form:

x ≥ − 30

Interval Notation:

[ − 30 , ∞ )

4 0
3 years ago
Thomas wants to put a fence around a rectangular garden that is 12 feet long and 7 feet wide.
Goshia [24]

Answer:

84 feet

Step-by-step explanation:

 he will need 84 ft to cover the entire garden

6 0
3 years ago
Read 2 more answers
A researcher planned a study in which a crucial step was offering participants a food reward. It was important that three food r
lbvjy [14]

Answer:

Step-by-step explanation:

Hello!

A pilot study was conducted to test if three food rewards are equally appealing to the participants.

Of 60 participants surveyed:

16 preferred cupcakes (CC)

26 preferred candy bars (CB)

18 preferred dried apricots (DA)

If the three types of food are equally appealing for the participants, you'd expect that their proportions will be equal: P(CC)=P(CB)=P(DA)= 1/3

1.

The objective of this pilot study is to test if the observed frequencies follow a theoretical model/ distribution. To analyze this, you have to apply a Chi Square Goodness to Fit test. X^2=sum \frac{(O_i-E_i)^2}{E_i} ~~X^2_{k-1} Where k= number of categories of the variable.

For this example the statistical hypotheses are:

H₀: P(CC)=P(CB)=P(DA)= 1/3

H₁: At least one of the proportions isn't equal to the others.

2.

To calculate the expected frequencies for each category you have to use the formula: E_i= n* P_i where Pi represents the theoretical proportion for the i category, stated in the null hypothesis.

E_{CC}= n* P(CC)= 60*1/3= 20

E_{CB}= n*P(CB)= 60*1/3= 20

E_{DA}= n* P(DA)= 60* 1/3= 20

3.

The cutoff or critical value indicates the beginning of the rejection region for the hypothesis test. For the Chi-Square tests, the rejection region is always one-tailed to the right, meaning that you'll reject the null hypothesis if the value of the statistic is big. For the goodness to fit test you have k-1 degrees of freedom, so the critical value will be:

Assuming α: 0.05

X^2_{k-1;1-\alpha /2}= X^2_{2;0.975}= 7.378

The rejection region is then X²₂ ≥ 7.378

4.

X^2_{H_0}= \frac{(O_{CC}-E_{CC})^2}{E_{CC}} + \frac{(O_{CB}-E_{CB})^2}{E_{CB}}  + \frac{(O_{DA}-E_{DA})^2}{E_{DA}} = \frac{(16-20)^2}{20} +\frac{(26-20)^2}{20} +\frac{(18-20)^2}{20}=  \frac{14}{5}= 2.8

I hope this helps!

5 0
3 years ago
7-7(5+x)-9x in simplified​
Luden [163]

Answer:

-28 - 16x

Step-by-step explanation:

7-7(5+x)-9x

Distribute

7 - 35 -7x -9x

Combine like terms

-28 - 16x

5 0
2 years ago
Solve 148×35. using us standard algorithm
lesya692 [45]
It would be 5180 for the answer
8 0
3 years ago
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